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ryzh [129]
2 years ago
10

Sami needs to decide how the fonts, colors, and images will look on her new web site. Which will help her pian her design?

Computers and Technology
1 answer:
shtirl [24]2 years ago
6 0
Maybe a sketchbook:))))
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How do you think weather can affect sailing?<br><br>What would be good sailing weather?​
N76 [4]

Answer:

Weather can affect sailing because if its raining it can sink it also if theres a storm. Good weather that would be good to sail in is if its a little windy because if its just sunny and not windy it wont move. ps you can copy it if u want idc

6 0
3 years ago
In C complete the following:
Crazy boy [7]

Answer:

#include <stdio.h>

void printValues ( unsigned char *ptr, int count) // count is no of cells

{

 for(int i=0; i<count; i++) {

   printf("%d ", ptr[i]);

 }

}

int main ( )

{

 unsigned char data[ ] = { 9, 8, 7, 5, 3, 2, 1} ;

 printValues( data, sizeof(data)/sizeof(data[0]) );

}

Explanation:

Remember that the sizeof() mechanism fails if a pointer to the data is passed to a function. That's why the count variable is needed in the first place.

3 0
3 years ago
Blair is the director of information systems at a marketing firm. She creates a set of guidelines that dictate everything an emp
gizmo_the_mogwai [7]

Answer:

data

Explanation:

Because i said so

4 0
3 years ago
What Are the Components of a Web Address? *​
ipn [44]

Answer:

What Are the Components of a Web Address?

1.Protocol. The first component of a web address is the protocol, which is also known as the scheme. ...

2.Domain Name. The domain name part of the web address is the unique identifier for the website on the internet. ...

3.Domain Extension. ...

4.Path & Filename.

5 0
3 years ago
Read 2 more answers
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
2 years ago
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