Answer:
B. Use cross-platform tools to write code that will translate the existing Android app code into different native formats.
Explanation:
Cross-platform application development tools are tools that can be used tool generate applications of different platforms, by just writing a single type of code. It has the ability to automatically create an application of a different platform from another.
A developer can develop an application like Android and convert it to IOS for Apple. Xamarin, Appcelerator coroner etc, are all examples of cross-platform tools.
I don’t really understand what you are trying to ask. Try posting a picture along with your question
The three options that describe the typographic hierarchy are given below:
- The importance of information is shown through the text.
- The presentation of the text in terms of structure.
- The placement of the text defines its flow and hierarchy.
Thus, the correct options are A, B, and C.
<h3>What is Typographic hierarchy?</h3>
Typographic hierarchy may be characterized as an approach that utilizes typography: the size, font, and layout of distinct text components to produce a hierarchical division that can authenticate users where to look for specific information.
The purpose of using this methodology is to focus on the main points of the article accordingly. It increases the sense of understanding of the readers with focus.
Therefore, it is well described above.
To learn more about Typographic hierarchy, refer to the link:
brainly.com/question/12076206
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Answer:
It can be a really good approach to use a local solver using the min conflicts heuristic in solving sudoku problems. It will work better actually. In this process, the value chosen is the value with the minimum conflicts. This is the general way a normal person would also tackle this problem. By this approach, if we keep taking the values with minimum conflicts the sudoku puzzle can be solved with a better performance.
Explanation:
Answer:
select style_name,br.name as brewery,count(beer_id) as Num
from beerdb.beers be
inner join beerdb.styles st
on be.style_id = st.style_id
join beerdb.breweries br on
be.brewery_id = br.brewery_id
group by style_name , br.name
having count(beer_id)>=10
order by style_name, num desc
Explanation:
