$\displaystyle y=x^3\\x=\sqrt[3]y\\\\V=\pi \int \limits_1^8(2^2-(\sqrt[3]y)^2)\, dy\\V=\pi \Big[4x-\dfrac{3}{5}x^{\tfrac{5}{3}}\Big]_1^8\\V=\pi \left(4\cdot8-\dfrac{3}{5}\cdot8^{\tfrac{5}{3}\right-\left(4\cdot1-\dfrac{3}{5}\cdot1^{\tfrac{5}{3}\right)\right)\\V=\pi \left(32-\dfrac{96}{5}-\left(4-\dfrac{3}{5}\right)\right)\\V=\pi \left(\dfrac{64}{5}-\dfrac{17}{5}\right)\\V=\dfrac{47\pi}{5}$

3 0

3 years ago

Help please solve for x

Y_Kistochka [10]

Answer: x= 47 (If that says 3x+2)(the picture is a little blurry)

Step-by-step explanation:

Linear pairs of angles sum to 180.

37+(3x+2) =180

Combine like terms

39+ 3x = 180

Subtract 39 from both sides

3x = 141

Divide both sides by 3

x= 47

3 0

3 years ago

Draw triangle pqr and name it's vertices sides and angles ​

Draw triangle pqr and name it's vertices sides and angles