Answer:
A. x=16
Step-by-step explanation:
Similar triangles/ratios
1. Substitute 2x + 7 = 39, 4x + 1 = 65
2. Find size ratio between the two figures, 5:3
3. Check for similarity - 39 x 5/3 = 65
Answer:
15.40(approximately).
Step-by-step explanation:
The current price is $750900.
The last year the price was $650700.
Amount increase in the price is $(750900 - 650700) = $100200.
Hence the percentage is
= 15.40 (approximately).
Answer:
Using either method, we obtain: 
Step-by-step explanation:
a) By evaluating the integral:
![\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7B%5Csqrt%5B8%5D%7Bu%5E3%7D%20%7D%20%5C%2C%20du)
The integral itself can be evaluated by writing the root and exponent of the variable u as: ![\sqrt[8]{u^3} =u^{\frac{3}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bu%5E3%7D%20%3Du%5E%7B%5Cfrac%7B3%7D%7B8%7D)
Then, an antiderivative of this is: 
which evaluated between the limits of integration gives:

and now the derivative of this expression with respect to "t" is:

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:
"If f is continuous on [a,b] then

is continuous on [a,b], differentiable on (a,b) and 
Since this this function
is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

Answer:
d.) simplify the expression inside the pipe symbols