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Mademuasel [1]
2 years ago
11

Write 6^-7 in form 1/a^n where n>1

Mathematics
2 answers:
GaryK [48]2 years ago
8 0

6^{-7} = 6^{0-7} =\dfrac{6^0}{6^7} = \dfrac 1{6^7}

laiz [17]2 years ago
7 0

Answer:

\frac{1}{6^{7}}

Step-by-step explanation:

6^{-7} is the same as \frac{1}{6^{7}} because the negative power (or exponent) tells us to find the reciprocal of the base number (in other words, turn it into a fraction in the form 1/x).

a = 6 and n = 7 which is greater than 1

Hope this helps!

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PLEASE ANSWER THIS QUESTION
N76 [4]

Answer:

Hi.

Step-by-step explanation:

Ask your teacher for help because your parents are paying the school fees. Feel free. If you want the answer still message back.

6 0
2 years ago
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
I need help with all of them.. Please help me
jarptica [38.1K]

Answer:

1. 8

2. 0.49

3. 7

4. 0.52

5. 0.43

6. 28

Step-by-step explanation:

I did the math you are welcome.

5 0
2 years ago
Which graph represents the solution of y > x2 + 2?
Vladimir [108]
The questions is asking which one and i say is graph B
4 0
2 years ago
Read 2 more answers
Pls help I dont get it​
iragen [17]

Answer:

y=4x

Step-by-step explanation:

The equation of a line is y=mx+b, where m is the slope and b is the y intercept.

The slope formula is Δy/Δx, so using the coordinates (1, 4) and (2, 8), the slope is \frac{8-4}{2-1} which equals 4.

The y intercept is 0.

Therefore, the equation is y=4x.

8 0
3 years ago
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