Question

A 45 gram sample of a substance that’s used to preserve fruit and vegetables has a K-value of 0.1085

Answer 1

Answer:

6.3 days

Step-by-step explanation:

The decay formula is

N(t) = N₀ exp(-kt)

where

N₀ = 45 g, original mass

N(t) = mass after time t, days

k = 0.1109, the decay constant.

At half life, N(t) = (1/2)*N₀. Therefore

1/2 = exp(-0.1109t)

Take natural log of each side.

ln(0.5) = -0.1109t

t = ln(0.5)/(-0.1109) = 6.25 days

Answer: 6.3 days (nearest tenth)