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CaHeK987 [17]
2 years ago
10

A 45 gram sample of a substance that’s used to preserve fruit and vegetables has a K-value of 0.1085

Mathematics
1 answer:
Anna007 [38]2 years ago
7 0

Answer:

6.3 days

Step-by-step explanation:

The decay formula is

N(t) = N₀ exp(-kt)

where

N₀ = 45 g, original mass

N(t) = mass after time t, days

k = 0.1109, the decay constant.

At half life, N(t) = (1/2)*N₀. Therefore

1/2 = exp(-0.1109t)

Take natural log of each side.

ln(0.5) = -0.1109t

t = ln(0.5)/(-0.1109) = 6.25 days

Answer: 6.3 days (nearest tenth)

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Answer:

144

Step-by-step explanation:

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2 years ago
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stack of mail consists of 8 bills, 10 letters, and 6 advertisements. One piece of mail is drawn at random and put aside. Then a
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INFORMATION:

We know that:

- stack of mail consists of 8 bills, 10 letters, and 6 advertisements.

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And we must find P (both are letters)

STEP BY STEP EXPLANATION:

To find the probability, we need to know that we have two events. First, when one piece of mail is drawn at random and put aside and, second, when a second piece of mail is drawn.

These two events are dependent. If A and B are dependent events, P(A and B) = P(A) • P(B after A) where P(B after A) is the probability that B occurs after A has occurred.

So, first

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P(A)=\frac{favorable\text{ }cases}{total\text{ cases}}=\frac{10}{24}

- Probability of B after A

Since A already occurred and one piece of the mail was drawn (a letter), now in total we would have 9 letter and 23 total pieces

P(B\text{ after }A)=\frac{9}{23}

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ANSWER:

P (both are letters) = 0.1630

8 0
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Answer:

Step-by-step explanation:

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Hope this helps!

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I think the answer would be the first one
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