Please help me slove this problem -4 = 2x

Solve for X. X/8 = 3 3/4 A. 30 B. 24 3/4 C.120 D.15/32

Feliz [49]

X / 8 = 3.75
X = 3.75 * 8
X = 30

6 0

3 years ago

Trigonometry

Alchen [17]

The area of the triangle PQR is 17.6 square units.

Explanation:

Given that the sides of the triangle are PQ = 12 and PR = 3 and $m\angle P = 78^{\circ}$

We need to determine the area of the triangle PQR

Area of the triangle:

The area of the triangle can be determined using the formula,

$\text {Area}=\frac{1}{2} qr \sin P$

Substituting the values, we get,

$\text {Area}=\frac{1}{2}(12)(3) \sin 78$

Simplifying, we have,

$\text {Area}=\frac{1}{2}(36)(0.98)$

Multiplying the terms, we have,

$\text {Area}=\frac{35.28}{2}$

Dividing, we get,

$\text {Area}=17.64$

Rounding off to the nearest tenth, we have,

$Area=17.6$

Thus, the area of the triangle PQR is 17.6 square units.

3 0

3 years ago

Read 2 more answers

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0

2 years ago

Identify the 33rd term of the arithmetic sequence 9, 7 and one half, 6...

marta [7]

Answer:

-39

Step-by-step explanation:

The general term of an arithmetic sequence is ...

an = a1 +d(n -1)

This sequence has first term a1=9 and common difference d=(7.5-9) = -1.5. Then the 33rd term is ...

a33 = 9 -1.5(33 -1) = 9 -48 = -39

The 33rd term is -39.

5 0

3 years ago

Jeremiah pays his tutor $35 per month. How much does Jeremiah spend per year for his tutor? $ Part B: Jeremiah's tutor gave him

tresset_1 [31]

Part A = 420
$35 \times 12 = 420$
Part B = -91

5 0

2 years ago

Read 2 more answers

Please help me slove this problem -4 = 2x - 8