6th grade math plz help?

Mathematics

2 answers:

Sergeu [11.5K]2 years ago

8 0

Answer:

about 83%

Why:

1/3 + 1/2 = 0.83333333333

0.83333333333 as a percentage is 83.333333333%

umka21 [38]2 years ago

4 0

Answer:

17%

Step-by-step explanation:

He completed 1/2 plus 1/3 of the painting.

The total he completed is

1/2 + 1/3 = 3/6 + 2/6 = 5/6

He needs to to 1 - 5/6 = 6/6 - 5/6 = 1/6 of the painting.

100% is the whole. He needs to do 1/6 of 100%.

1/6 * 100% = 100%/6 = 16.666...%

Answer: 17%

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FInd the surface area of the triangular prism

Marta_Voda [28]

Answer:

273.7

Step-by-step explanation:

first fine the sides that isn't the base.

triangle area formula: (b*h)/2

(14*9)/2 = 63

since there are 3 sides you multiply this by three.

63*3=189

then find the base.

same formula since its a triangle.

(12.1*14)/2 = 84.7

now add them both up:

84.7+189 = 273.7

hope this helps!

3 0

3 years ago

Read 2 more answers

|-9c|=8 and solve for c

melisa1 [442]

C = negative 8/9 or 8/9

5 0

3 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .