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2 years ago

6th grade math plz help?

Mathematics

2 answers:

Sergeu [11.5K]2 years ago

8 0

Answer:

about 83%

Why:

1/3 + 1/2 = 0.83333333333

0.83333333333 as a percentage is 83.333333333%

umka21 [38]2 years ago

4 0

Answer:

17%

Step-by-step explanation:

He completed 1/2 plus 1/3 of the painting.

The total he completed is

1/2 + 1/3 = 3/6 + 2/6 = 5/6

He needs to to 1 - 5/6 = 6/6 - 5/6 = 1/6 of the painting.

100% is the whole. He needs to do 1/6 of 100%.

1/6 * 100% = 100%/6 = 16.666...%

Answer: 17%

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Solve the compound inequality 9x ≤ –27 or 4x ≥ 36.

leva [86]

Answer:

x ≤ – 3 or x ≥ 9.

Step-by-step explanation:

Given : 9x ≤ –27 or 4x ≥ 36.

To find : Solve the compound inequality.

Solution : We have given 9x ≤ –27 or 4x ≥ 36.

For 9x ≤ –27 .

On dividing both sides by 9.

x ≤ – 3.

For , 4x ≥ 36.

On dividing both sides by 4.

x ≥ 9.

We can write x ≤ – 3 or x ≥ 9.

Therefore, x ≤ – 3 or x ≥ 9.

3 0

3 years ago

Complete the inequality statement. 24 g_1,679 mg оно V

Darina [25.2K]

The answer is 24 grams > 1.679 grams

Hope this helps <3

5 0

2 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.

andreyandreev [35.5K]

The products of the polynomials are:

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
(x - y) * (x + 3y) = x² + 2xy + 3y²
(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18
(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6
(x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9) = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

5 0

1 year ago

The heights of young women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Young men the same age have heights d

murzikaleks [220]

Answer: 10.703%

Step-by-step explanation:

Let minimum height of the tallest 25% of young women be M.

Let Q be the random variable which denotes the height of young women.

Therefore, Q – N(64,2.70)

Now, P(Q˂M) = 1-0.25

i.e. P[(Q-64)/2.7 ˂ (M-64)/2.7] = 0.75

I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches

Let R be the random variable denoting the height of young men

Therefore, R – N (69.3, 2.8)

i.e. (R-69.3)/2.8 – N(0,1)

therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]

this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033

From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%

4 0

3 years ago

How to solve this question?

Arisa [49]

F(g(x)) where you see an 'x' in f(x) put a g:

f(g(x)) = 1/(g-7), now step by step: g - 7 = 6/x+7-7=6/x, and 1/(g-7)=1/(6/x)=x/6!

I let the second one for you. Sorry if you disagree!

4 0

3 years ago