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Reil [10]
3 years ago
15

What is the volume of the triangular Prism

Mathematics
1 answer:
baherus [9]3 years ago
4 0
It is probably A. A is the most reasonable answer.
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HELP PLEASE NEED IT THANKS
Naya [18.7K]
<h3>Hello there i hope you are having a great day :) </h3><h3>Shop A   Shop B </h3><h3>55            36 </h3><h3>52            40 </h3><h3>50            34 </h3><h3>47            39 </h3><h3>51             44 </h3><h3>48            41 </h3><h3>53            40 </h3><h3>53            38</h3><h3>1) Mean for both coffee shops = Shop A = 409 ÷ 8 = 51.125 Shop B = 312 ÷ 8 = 39.</h3><h3>2) Mean for Shop B = 39</h3><h3>3) Mean for Shop A = 51.125</h3><h3>4) Median for Shop A = 52</h3><h3>5) Median for Shop B =  39</h3><h3>Hopefully this well help you :)</h3>
5 0
3 years ago
15 pts. Prove that the function f from R to (0, oo) is bijective if - f(x)=x2 if r- Hint: each piece of the function helps to "c
solniwko [45]

Answer with explanation:

Given the function f from R  to (0,\infty)

f: R\rightarrow(0,\infty)

-f(x)=x^2

To prove that  the function is objective from R to  (0,\infty)

Proof:

f:(0,\infty )\rightarrow(0,\infty)

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let f(x_1)=f(x_2)

(x_1)^2=(x_2)^2

Cancel power on both side then we get

x_1=x_2

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get y=x^2

x=\sqrt y

The value of y is taken from (0,\infty)

Therefore, we can find pre image  for every value of y.

Hence, the function is onto function on domain (0,\infty)

Therefore, the given f:R\rightarrow(0.\infty) is bijective function on (0,\infty) not on  whole domain  R .

Hence, proved.

3 0
3 years ago
F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x
olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

V=9\int\limits^2_0 {4y^{3}/3} \, dy

After performing the elementary y integral we obtain the desired volume as below,

V= 48 units^{3}

4 0
3 years ago
PLEASE HELP!!
Dima020 [189]

Answer:

A. 90°+m∠4

Step-by-step explanation:

Also  

∠ A + ∠ C = 180  o = ∠ B + ∠ D

⇒ 2 x+ ( 3 x − 5 ) = 180  0 = ( x + 5 ) +  ∠  C

5 x  −  5  =  180

Add 5 to both sides

5 x  =  185

Divide both sides by 5

x =  185  5  =  37

But it was A. 90°+m∠4

4 0
2 years ago
Help me??? Please it’s urgent
Elodia [21]

The answer is option 2.

8 0
3 years ago
Read 2 more answers
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