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lina2011 [118]
3 years ago
7

Which of the following describes the way substances diffuse in and out of a cell?

Mathematics
2 answers:
maria [59]3 years ago
6 0

Answer:

the answer is D.

Step-by-step explanation:

im answering so the other person can get brainliest :)

☁️☁️☁️☁️☁️☁️

frez [133]3 years ago
5 0

Answer:

Its D. Substances move greater to lesser concentration

In simple diffusion, small noncharged molecules or lipid soluble molecules pass between the phospholipids to enter or leave the cell, moving from areas of high concentration to areas of low concentration (they move down their concentration gradient). Oxygen and carbon dioxide and most lipids enter and leave cells by simple diffusion.

 

Have a nice day

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HELP ME I WILL MARK BRAINLIEST
Westkost [7]

Answer:

The answer is 1/15

I hope it helps

7 0
3 years ago
A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m,
BlackZzzverrR [31]

Answer:

301.4

Step-by-step explanation:

Volume of a cylinder=pi*r^{2}*h.  Assuming you want 3.14 for pi, we can substitue the 4m for r, 6 for h and 3.14 for pi.

V=3.14*4^{2}*6

V=301.44

Since you want to round to nearest tenths, the answer is 301.4

8 0
3 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
NEED HELP ASAP<br><br>3(x+2)=18​
elena-14-01-66 [18.8K]

Answer:

x=4

Step-by-step explanation:

3x + 6 = 18

3x = 18 - 6 = 12

x = 4

4 0
2 years ago
Read 2 more answers
Find the volume of each figure. Round your answers to the nearest hundredth, if necessary
SCORPION-xisa [38]

Answer:

666.67π .ft^3

<em>here's</em><em> your</em><em> solution</em>

<em>=</em><em>></em><em> </em><em>radius</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ft</em>

<em>=</em><em>></em><em> </em><em>height</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>ft</em>

<em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>πr^</em><em>2</em><em>h</em><em>/</em><em>3</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>radius</em><em> and</em><em> height</em><em> </em>

<em>=</em><em>></em><em> </em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>^</em><em>2</em><em>*</em><em>2</em><em>0</em><em>/</em><em>3</em><em>π</em>

<em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>6</em><em>6</em><em>6</em><em>.</em><em>6</em><em>7</em><em>π</em><em> </em><em>.</em><em>ft^</em><em>3</em>

<em>hope</em><em> it</em><em> helps</em>

5 0
2 years ago
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