The equation is already is slope intercept form where you can easily point out the gradient, or the slope, and the y intercept.
y=mx+b where m is the gradient, and b is the y intercept.
Since there is no m, the gradient is 1.
The y intercept had x=0 and y=b
b in this case is 6
the y intercept= (0,6)
The choices are found elsewhere and the figures would be:
a. rectangleb. trianglec. squared. trapezoid
From the choices, the answer would be option B. A triangle figure would be the cross section when <span>a rectangular pyramid that has been intersected by a plane perpendicular to its base and through</span>its vertex.
We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.
First of all, we will draw a triangle as shown in the attachment.
We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.
We know that sine relates opposite side of right triangle to hypotenuse.
Using inverse sine or arcsin, we will get:
Upon rounding to nearest degree, we will get:
Therefore, the measure of angle J is approximately 24 degrees.
Answer:
15 if b is supposed to the side length, √15 if b is the base which is a square.
Step-by-step explanation: