Answer:
The margin of error for a sample size of 250 is 6
Step-by-step explanation:
The margin of error is given as
1/square root of the sample size
Thus, margin of error for a sapless size of 250 is
1/√250
= 1/15. 811
= 6
Answer:
Step-by-step explanation:
I hope I did this right:
So first thing to do is set up the equation.
Next thing to to is subtract 1/3 from both sides to get:
Next up, you will multiply each of the fractions by the opposing value
(multiply 1/8 by 3 and 1/3 by 8)
Alright almost done, by multiplying 24 by 5 you get 120, that will go in the numerator to make the math a lot easier.
K =
Finally, you subtract 123 over 24 by 8 over 24.
K =
Then just simplfy the 115/24 to get
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
Answer:
w = (cv +dy) / (cb - ad)
Step-by-step explanation:
Multiply through by c
aw + y = c(bw + v) / d Multiply by d
d(aw + y) = c(bw + v) Remove the brackets
daw + dy = cbw + cv Subtract dy from both sides.
daw +dy - dy = cbw + cv -dy
daw = cbw + cv - dy Subtract cbw from both sides
daw - cbw = cbw - cbw + cv - dy
daw - cbw = cv - dy Isolate W on the left.
w(da - cb) = cv - dy Divide by cb - ad on both sides.
w = (cv - dy) / (ad - bc) Answer