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DochEvi [55]
3 years ago
7

What is the IQR of: 44, 38, 51, 59, 53, 47, 52 i forget how to do iqr lol

Mathematics
1 answer:
jasenka [17]3 years ago
7 0

Answer: 9

Step-by-step explanation:

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Pls help it is too hard​
ozzi
U have to substitute in the values of x to get the values of y

answers in order from left to right:
4.5, 4, 3.5, 3, 2.5, 2

ex of solving process:
x+2y=7
(-2)+2y=7
2y=9
y=4.5
3 0
3 years ago
Read 2 more answers
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
Tickets to a concert cost $2 for children, $3 for teenagers and $5 for adults. When 570 people attended the concert, the total t
aalyn [17]

Answer:

B

Step-by-step explanation:

220*5= $1100

=$1950 - $1100 = $850

=$850/5(both children and teenagers added together) = 170

3 0
3 years ago
Read 2 more answers
A snack-size bag of M&amp;Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 y
Anestetic [448]

Answer:

\frac{1}{4180}

Step-by-step explanation:

GIVEN: A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in succession, without replacement.

TO FIND: What is the probability that the first two candies drawn are orange and the third is green.

SOLUTION:

Total  candies in the bag =57

Probability that first ball is orange, P(A)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}

                                                       =\frac{3}{57}=\frac{1}{19}

Probability that second ball is orange, P(B)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}

                                                        =\frac{2}{56}=\frac{1}{28}

Probability that third ball is green, P(C)=\frac{\text{total green candies in bag}}{\text{total candies in bag}}

                                                                 =\frac{7}{55}

Now, probability that first two balls are orange and third is green is

=P(A)\times P(B)\times P(C)

=\frac{1}{19}\times\frac{1}{28}\times\frac{7}{55}

=\frac{1}{19}\times\frac{1}{4}\times\frac{1}{55}

=\frac{1}{4180}

Hence,  probability that first two balls are orange and third is green is \frac{1}{4180}

3 0
4 years ago
It rain 10% of the 30 days last month. On how many days did it not rain?
alexdok [17]
Ok. You need to find the 10% of days it did rain. Since there were 30 days, ten percent of that would be 3 days. So it rained three days. If there were 30 days, then 30-3=27 days it did not rain. 
8 0
4 years ago
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