Mia recipe requires the mixing of tsp chili powder with 1 tsp of salt. She only has 1 tsp of salt, so based on the ratio of chil
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Answer:
Step-by-step explanation:
Hello!
(Data and full text attached)
The stem and leaf plot is a way to present quantitative data. Considering two-digit numbers, for example 50, the tens digits are arranged in the stem and the units determine the leafs.
So for the stem and leaf showing the digs of the top players of the tournament, the observed data is:
41, 41, 43, 43, 45, 50, 52, 53, 54, 62, 63, 63, 67, 75, 97
n= 15
Note that in the stem it shows the number 8, but with no leaf in that row, that means that there were no "eighties" observed.
a) 6 Players had more than 60 digs.
b)
To calculate the mean you have to use the following formula:
X[bar]= ∑x/n= (41 + 41 + 43 + 43 + 45 + 50 + 42 + 53 + 54 + 62 + 63 + 63 + 67 + 75 + 97)/15= 849/15= 56.6 digs
To calculate the median you have to calculate its position and then identify its value out of the observed data arranged from least to greatest:
PosMe= (n+1)/2= (15+1)/2= 8 ⇒ The median is in the eight place:
41, 41, 43, 43, 45, 50, 42, 53, 54, 62, 63, 63, 67, 75, 97
The median is Me= 53
53 is the value that separates the data in exact halves.
The mode is the most observed value (with more absolute frequency).
Consider the values that were recorded more than once
41, 41
43, 43
63, 63
41, 43 and 63 are the values with most absolute frequency, which means that this distribution is multimodal and has three modes:
Md₁: 41
Md₂: 43
Md₃: 63
The Range is the difference between the maximum value and the minimum value of the data set:
R= max- min= 97 - 41= 56
c)
The distribution is asymmetrical, right skewed and tri-modal.
Md₁: 41 < Md₂: 43 < Me= 53 < X[bar]= 56.6 < Md₃: 63
Outlier: 97
d)
An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.
Considering the 1st quartile (Q₁), the 3rd quartile (Q₃) and the interquartile range IQR, any value X is considered an outlier if:
X < Q₁ - 1.5 IQR
X > Q₃ + 1.5 IQR
PosQ₁= 16/4= 4
Q₁= 43
PosQ₃= 16*3/4= 12
Q₃= 63
IQR= 63 - 43= 20
Q₁ - 1.5 IQR = 43 - 1.5*20= 13 ⇒ There are no values 13 and below, there are no lower outliers.
Q₃ + 1.5 IQR = 63 + 1.5*20= 93 ⇒ There is one value registered above the calculated limit, the last observation 97 is the only outlier of the sample.
The mean is highly affected by outliers, its value is always modified by the magnitude of the outliers and "moves" its position towards the direction of them.
Calculated mean with the outlier: X[bar]= 849/15= 56.6 digs
Calculated mean without the outlier: X[bar]= 752/14= 53.71 digs
I hope this helps.
9514 1404 393
Answer:
7 square units
Step-by-step explanation:
There are several ways the area of triangle EBD can be found.
- find the lengths EB, BD, DE and use Heron's formula (messy due to roots of roots being involved).
- define point G at the lower left corner and subtract the areas of ∆DEG and BCD from trapezoid BCGE.
- figure the area from the coordinates of the vertices.
- use Pick's theorem and count the dots.
We choose the latter.
__
Pick's theorem says the area of a polygon can be found as ...
A = i + b/2 -1
where i is the number of grid intersection points interior to the polygon, b is the number of grid points intersected by the border.
The attached figure shows the lines EB, BD, and DE intersect one point in addition to the vertices. So, b=4. A count of the red dots reveals 6 interior points (i=6). So, the area is ...
A = 6 + (4/2) -1 = 7
The area of ∆EBD is 7 square units.
Answer:(6,-2)
Step-by-step explanation:
M is the midpoint of AB then ,
M =
,
,
,
so, B= (6,-2)