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Rom4ik [11]
3 years ago
13

PLEASE HELP ASAP!! DUE TONIGHT!! THANKS

Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Answer:

what ever sides are multiply the points by 2 each (x time 2, y times 2) Best I got. Hope this helps some

Step-by-step explanation:

figure out the sides then:

Ex. Perform a Dilation of 4 on point A (2, 3) which you can see in the picture below. Multiply the coordinates of the original point (2, 3), called the image, by 4. Image's coordinates = (2 * 4, 3 * 4) to get the coordinates of the image (8, 12).

Since this is the area x 2, multiply 84x2

You might be interested in
A genetic experiment involving peas yielded one sample of offspring consisting of 409 green peas and 171 yellow peas. Use a 0.05
grigory [225]
The usual expectation for this kind of experiment is that the peas would yield green and yellow peas in a 3:1 ratio, or 75% green to 25% yellow. So your null hypothesis is that the proportion of yellow peas is p=0.25.

You're testing the claim that 26% of the offspring will be yellow, which means the alternative hypothesis is that the proportion of yellow peas is actually 0.26, or more generally that the expected proportion is greater than 0.25, or p>0.25.

The test statistic in this case will be

Z=\dfrac{\hat p-p_0}{\sqrt{\dfrac{p_0(1-p_0)}n}}

where p_0 is the proportion assumed under the null hypothesis, \hat p is the measured proportion, and n is the sample size. You have p_0=0.25, \hat p=\dfrac{171}{171+409}\approx0.29, and n=409+171=580, so the test statistic is

Z=\dfrac{0.29-0.25}{\sqrt{\dfrac{0.25\times0.75}{580}}}\approx2.2247

Because you're testing p>p_0, this is a right-tailed test, so the P-value is

\mathbb P(Z>2.2247)\approx0.0131

The critical value for a right-tail test at a 0.05 significance level is Z_\alpha\approx1.6449, which means the rejection region is any test statistic that is larger than this critical value. Since Z>Z_\alpha in this case, we reject the null hypothesis.

So the conclusion for this test is that the sample proportion is indeed statistically significantly different from the proportion suggested by the null hypothesis.
8 0
3 years ago
Read 2 more answers
Get the general term for the sequence being your t3 = 11 and the t20 = 244.2
marusya05 [52]

Answer:

nth term = t_{n} = 7.639(1.2)^{n - 1}

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = t_{3} = ar^{2} = 11 .......... (1) and  

20th term = t_{20} = ar^{19} = 244.2 ........... (2)

Now, dividing equation (2) with equation (1) we get

\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2

⇒ r^{17} = 22.2

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = t_{n} = 7.639(1.2)^{n - 1} (Answer)

5 0
3 years ago
Write the following expression with as few symbols as possible, using the notational conventions:
My name is Ann [436]

Answer:

The simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.

Step-by-step explanation:

The expressions provided are:

(i)\ x+((y\times (z')) +t)\\\\(ii)\ x\times((x+(y'))+z)

(i)

Simplify the first expression with as few symbols as possible:

x+((y\times (z')) +t)=x+(yz'+t)

                              =x+yz'+t

(ii)

Simplify the second expression with as few symbols as possible:

x\times((x+(y'))+z)=x\times ((x+y')+z)

                              =x (x+y'+z)

Thus, the simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.

6 0
4 years ago
I need help guys plsss
malfutka [58]

Answer:

6. r = 21 cm

7. A = 155.5 m²

Step-by-step explanation:

7: Formula for arc length is;

S = (θ/360) × 2πr

We are given;

S = 51 cm

θ = 139°

Thus;

51 = (139/360) × 2π × r

Making r the subject;

r = (51 × 360)/(2π × 139)

r ≈ 21 cm

8) Area of sector is gotten from the formula;

A = (θ/360) × πr²

A = (220/360) × (π × 9²)

A = 155.5 m²

8 0
3 years ago
Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)​
Mrrafil [7]

The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Step-by-step explanation:

Given polynomials are:

(x^3+3x^2+1)\\and\\(3x^2+6x-2)

In order to multiply both polynomials, we will use the distributive property

So,

= (x^3+3x^2+1)(3x^2+6x-2)\\=x^3(3x^2+6x-2)+3x^2(3x^2+6x-2)+1(3x^2+6x-2)\\=3x^5+6x^4-2x^3+9x^4+18x^3-6x^2+3x^2+6x-2

Combining like terms

=3x^5+6x^4+9x^4-2x^3+18x^3+3x^2-6x^2+6x-2\\=3x^5+15x^4-16x^3-3x^2+6x-2

Hence,

The product of given polynomials is: 3x^5+15x^4-16x^3-3x^2+6x-2

Keywords: Polynomials, variables

Learn more about polynomials at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

#LearnwithBrainly

6 0
4 years ago
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