Question

What is the specific heat of a 123 g substance that requires 4.56 J of heat in

Answer 1

Answer:  A. $0.00301J/g^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed  = 4.56 J

m = mass of substance = 123 g

c = specific heat capacity = ?

Change in temperature ,$\Delta T=T_f-T_i=12.32^0C$

Putting in the values, we get:

$4.56J=123g\times c\times 12.32^0C$

$c=0.00301J/g^0C$

The specific heat of a 123 g substance that requires 4.56 J of heat in  order to increase its temperature by 12.32 °C is $0.00301J/g^0C$