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Fynjy0 [20]
3 years ago
7

What is the value of x in the equation x-ty= 30, when y = 15? 4 8 80 200

Mathematics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

2

Step-by-step explanation:

Assuming that you mean x is t, then the answer is 2.

You plug in 15 for y, and you have this: 15t=30

Divided both sides by 15, and you get t = 2

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2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


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