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3 years ago

12+18n+7-14n write an equivalent expression using like terms

Mathematics

1 answer:

spin [16.1K]3 years ago

3 0

You can get a similar expression with the same value by simplifying the expression.

19 + 4n

Hope this helps!

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Mila and samuel had an equal amount of money for shopping. Mila spent $42 and Samuel spent $36. After that, Mila had 1/2 of what

koban [17]

Answer:

Mila had $48 initially

Step-by-step explanation:

Let the amount of money they had be x

Mila spent $42; what is left would be x-42

Samuel spent $36: what is left would be x-36

So, what Mila had left is half of what Samuel has; that would be;

x-42 = 1/2(x-36)

2(x-42) = x -36

2x-84 = x -36

2x - x = 84 -36

x = $48

6 0

2 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

I need help I’m stuck

cluponka [151]

Answer:

Step-by-step explanation:

5 0

2 years ago

Question: what is the relationship between measures of angle 1 and angle 2

marusya05 [52]

Answer:

Step-by-step explanation:

m1 is greater than m2 because the angle is larger

4 0

3 years ago

How does the numbers of zeros in the product of 8 and 5000 compare to the number of zeros in the factors?

o-na [289]

If product means to multiply than
5000*8= 40000
Answer: There is one more zero in the product.

6 0

3 years ago