Answer:
bbbbvhxzjcxhchghghxcfafhfhgvbgfgxhghhfgyfyfggffffffffffff
<h3>
Answer: 6 ounces</h3>
========================================================
Work Shown:
(6 servings)/(4 oz of sauce) = (8 servings)/(x oz of sauce)
6/4 = 8/x
6*x = 4*8
6x = 32
x = 32/6
x = 5.333 approximately
x = 6 we round up despite 5.333 being closer to 5, than it is to 6.
If we went with 5 ounces, then we wouldn't clear the hurdle needed to serve 8 people.
The section below goes over why this is the case in more detail.
---------
6 servings : 4 ounces
6/4 servings : 4/4 ounces
1.5 servings : 1 ounce
So one ounce of sauce gets us 1.5 servings.
If we multiply both sides by 5, then,
1.5 servings : 1 ounce
5*1.5 servings : 5*1 ounce
7.5 servings : 5 ounces
This shows that 5 ounces of sauce will only produce 7.5 servings, which comes up short compared to 8 servings.
If we multiplied both sides by 6, then
1.5 servings : 1 ounce
6*1.5 servings : 6*1 ounce
9 servings : 6 ounces
This shows that 6 ounces of sauce yields 9 servings. We've gone overboard, but it's better to do that than come up short.
Answer:
Blank 1: 64° (or 32°, depending on what the label applies to)
Blank 2: 42
Step-by-step explanation:
It is a common mistake to believe you have solved the problem when you have found the value of the variable(s) in the problem. You have correctly found the values of n (42) and m (9). However, that is not what the problem is asking for.
We cannot tell if the value (1/2n+11)° is referring to angle DAB, or to angle CAB. In any event, (1/2n+11)° = (1/2×42 +11)° = 32°.
If that is angle CAB, then angle DAB is twice that value, 64°.
If that is angle DAB, then angle DAB is 32°.
__
The side length CD is the same as any other side length in a rhombus, so ...
CD = 4m+6 = 4×9 +6
CD = 42 . . . . units
Answer:
The area of the logo is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of a semicircle is equal to

so
The area of the logo is equal to multiply by 3 the area of one semicircle

we have
-----> the radius is half the diameter
substitute
