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Stels [109]
4 years ago
7

What atomic or hybrid orbitals make up the sigma bond between ge and h in germanium hydride, geh4 ?

Chemistry
2 answers:
ozzi4 years ago
8 0
<span>Germane is the chemical compound with the formula GeH₄, and the germanium analogue of methane. It is the simplest germanium hydride and one of the most useful compounds of germanium.


</span>In chemistry, sigma bonds (σ bonds) are the strongest type of covalent chemical bond. They are formed by head-on overlapping between atomic orbitals. Sigma<span> bonding is most simply defined for diatomic molecules using the language and tools of symmetry groups.
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
ludmilkaskok [199]4 years ago
6 0

Answer:

Electron geometry: tetrahedral, sp3 hybridized.

Explanation:

Hello,

Since four atoms of hydrogen are surrounding the germanium in this case, a sp3 hybrization is making up the sigma bons for this molecular compound. The germanium atom can use its singly occupied p-type orbitals, to form two covalent bonds with two hydrogen atoms, and use the s and the other p to form the other two covalent bonds with the remaining hydrogens.

Best regards.

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If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p
ElenaW [278]

Answer:

2.0 atm is the difference between the ideal pressure and  the real pressure.

Explanation:

If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C

Moles of argon = n = 1.00 mol

Volume of the container,V  = 0.500 L

Ideal pressure of the gas = P

Temperature of the gas,T = 27 °C = 300.15 K[/tex]

Using ideal gas equation:

PV=nRT

P=\frac{1.00 mol\times 0.0821 L atm/mol K\times 300.15 K}{0.500 L}=49.28 atm

Vander wall's of equation of gases:

The real pressure of the gas= p_v

For argon:

a=1.345 L^2 atm/mol^2

b=0.03219 L/mol.

(p_v+(\frac{an^2}{V^2})(V-nb)=nRT

(p_v+(\frac{(1.345 L^2 atm/mol^2)\times (1.00 mol)^2}{(0.500 L)^2})(0.500 L-1.00 mol\times 0.03219L/mol)=1.00 mol\times 0.0821 L atm/mol K\times 300.15 K

p_v = 47.29 atm

Difference :p - p_v= 49.28 atm - 47.29 atm = 1.99 atm\approx 2.0 atm

2.0 atm is the difference between the ideal pressure and  the real pressure.

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This refers to the speed of an object at a specific moment in time​
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Hydrogen is 99% H-1, 0.8% H-2 , and 0.2 H-3. calculate its average atomic mass
AlekseyPX
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Now, examining each of the choices:
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2- HBr and NaCl: since HBr is a strong acid while NaCl is the salt of another different acid, thus this mixture is not a buffer
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Explanation:

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