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BartSMP [9]
3 years ago
8

-3q + 12 greater than equal too 4q - 30 solve for q

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0

Solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Step-by-step explanation:

We need to solve the inequality: -3q+12\geq 4q-30 and find value of q

Solving:

-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6

So, solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Keywords: Solving inequality

Learn more about solving inequality at:

  • brainly.com/question/7490805
  • brainly.com/question/9590016
  • brainly.com/question/2840217

#learnwithBrainly

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16m^4-121 =(4m^2-11)(4m^2+11)

8 0
2 years ago
What is the slope of a linear that is perpendicular to the line y=-1/2x+5?​
Vlada [557]

Step-by-step explanation:

Equation of given line is:

y =  -  \frac{1}{2} x + 5 \\  \\ equating \: it \: with \: y =m_1x + c  \\ we \: find \:  \\ m_1 = -  \frac{1}{2} \\ let \: m_2 \: be \: the \: slope \: of \: required \: line \\  \\  \therefore \: m_1 \times m_2 =  - 1( \because \: lines \: are \:  \perp) \\  \\ \therefore \: -  \frac{1}{2} \times m_2 =  - 1\\  \\ \therefore \: m_2 = 2 \\

Thus, the slope of required line is 2.

6 0
3 years ago
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Ipatiy [6.2K]
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7 0
3 years ago
Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =
DanielleElmas [232]

Answer:

c = 5

Step-by-step explanation:

Given

f(c) = M

f(x) = x^2 - x + 1

Interval: [1,8]

M = 21

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

f(x) = x^2 - x + 1

f(1) = 1^2 - 1 + 1

f(1) = 1

f(x) = 8^2 - 8 + 1

f(x) = 57

1 \le M \le 57

1 \le 21 \le 57

M is within range.

Solving further:

We have:

f(c) = f(x) = M

f(x) = 21

Substitute 21 for f(x) in f(x) = x^2 - x + 1

21 = x^2 - x + 1

Express as quadratic function

x^2 - x + 1 - 21  = 0

x^2 - x - 20  = 0

Expand

x^2 + 4x - 5x - 20

x(x+4)-5(x+4)=0

(x - 5)(x+4) = 0

x - 5 = 0 or x + 4= 0

x = 5 or x = -4

The value of x = -4 is outside the Interval: [1,8]

So:

x = 5

f(c) = f(x) = M

f(c) = f(5) = 21

By comparison:

c = 5

4 0
2 years ago
Help plss.............
Svet_ta [14]

Answer:

The total cost would be 29.15$

Step-by-step explanation:

multiply 27.50 by 0.06 to get 1.65. Then add 27.50 and 1.65, to get 29.15

4 0
3 years ago
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