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Leno4ka [110]
3 years ago
15

2 7/10 -1 1/4 solving fractions

Mathematics
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer:

the answer would be

Hope that helps! :)

Step-by-step explanation:

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2x=-y in standard form
IgorC [24]

Answer:

y=-2x

Step-by-step explanation:

4 0
3 years ago
HELP! PLEASE! I really need help with this question!
LekaFEV [45]

Answer:

They are at the same height at 1.13 seconds.

Step-by-step explanation:

Remark

The rockets are at the same height when  f(x) = g(x) [see below] are the same. So you can equate them.

Givens

f(x) = - 16x^2 + 74x + 9

g(x) = -16x^2 + 82x              I have changed this so you don't have 2 f(x)s

Solution

  • f(x) = g(x)
  • -16x^2 + 74x + 9 = -16x^2 + 82x                        Add:  16x^2 to both sides
  • -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x   Combine terms
  • 74x + 9 = 82x                                                     Subtract 74x from both sides
  • 74x - 74x + 9 = 82x - 74x                                  Combine
  • 9 = 8x                                                                 Divide by 8
  • 9/8 = 8x/8
  • x = 1 1/8                                                              Convert to decimal
  • x = 1.125
  • x = 1.13  [rounded]


6 0
3 years ago
Can someone please help me
lisov135 [29]

Answer:

5.83 or E

Step-by-step explanation:

Use Pythagorean theorem. 5^2+3^2=c^2 because the diameter is perpendicular it cuts the chord in half.

25+9=c^2  

34=c^2

5.83

8 0
3 years ago
Read 2 more answers
The value of 23 + 33
ikadub [295]

Answer:

56 hope it helps....

hhcxxghjo9

4 0
3 years ago
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AB has endpoints at A(2,6) and B(6,8). What are the coordinates of the midpoint
Trava [24]

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>(</em><em>4</em><em>,</em><em>7</em><em>)</em>

<em>look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

6 0
3 years ago
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