Question

When the fifth term of an arithmetic sequence whose  common difference is D=six and whose first term is a1 =four

Answer 1

Answer:

28 is the answer

Step-by-step explanation:

in an arithmetic sequence nth term An is given by the equation

$an \: = a1 + (n - 1) \times d$

where A1 is first term and d is common difference. thus from the question we have

$a5 = 4 + ((5 - 1) \times 6) \\ = 4 + (4 \times 6) \\ = 4 + 24 \\ = 28$