Answer:
1/7
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(3-2)/(3-(-4))
m=1/(3+4)
m=1/7
We are concern about the vector (x-x0, y-y0, z-z0)
equaling to 5.
This happens
when √(x-x0)^2 + (y-y0)^2 + (z-z0)^2 = 5
Square
both side:
(x-x0)^2
+ (y-y0)^2 + (z-z0)^2 = 25 , a sphere
Which you will
recognize as a circle of radius one centered at (x0, y0, z0)
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1. Regroup terms
x(x+5)=104
2. Expand
x^2+5x=104
3. Move all terms to one side
x^2+5x-104=0
4. Factor x^2+5x-104
(x-8)(x+13)=0
5. Solve for x
x=8 or x=-13
Since x<0 is not possible in this case, x=8
6. Finding the dimensions
We know that one side has to be x+5, and now that we know x:
8+5=13
13*8=104
The dimensions are 13 and 8, have a nice day :D
The answer would be (0,5)
