Answer:
pls show the model
Step-by-step explanation:
Answer: First Option
![f (x) = (x-1) ^ 2 + 3](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%28x-1%29%20%5E%202%20%2B%203)
Step-by-step explanation:
Quadratic quadratic functions have the following form:
![f (x) = (x-h) ^ 2 + k](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%28x-h%29%20%5E%202%20%2B%20k)
Where the point (h, k) is the vertex of the function.
For a quadratic function of the form
the vertex of the function is at the point ![(-\frac{b}{2a}, f(\frac{-b}{2a}))](https://tex.z-dn.net/?f=%28-%5Cfrac%7Bb%7D%7B2a%7D%2C%20f%28%5Cfrac%7B-b%7D%7B2a%7D%29%29)
In this case the function is: ![f(x) = 4 + x^2 - 2x\\\\f(x)=x^2 -2x +4](https://tex.z-dn.net/?f=f%28x%29%20%3D%204%20%2B%20x%5E2%20-%202x%5C%5C%5C%5Cf%28x%29%3Dx%5E2%20-2x%20%2B4)
Then:
![a=1\\b=-2\\c=4](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-2%5C%5Cc%3D4)
The vertex is:
![(-\frac{(-2)}{2(1)}, f(\frac{2}{2(1)}))](https://tex.z-dn.net/?f=%28-%5Cfrac%7B%28-2%29%7D%7B2%281%29%7D%2C%20f%28%5Cfrac%7B2%7D%7B2%281%29%7D%29%29)
![(1, f(1))](https://tex.z-dn.net/?f=%281%2C%20f%281%29%29)
Note that
![f(1) = (1)^2 -2(1) +4\\\\f(1)=1-2+4=3](https://tex.z-dn.net/?f=f%281%29%20%3D%20%281%29%5E2%20-2%281%29%20%2B4%5C%5C%5C%5Cf%281%29%3D1-2%2B4%3D3)
Therefore the vertex is the point ![(1, 3)](https://tex.z-dn.net/?f=%281%2C%203%29)
Finally we have that ![h=1,\ k=3](https://tex.z-dn.net/?f=h%3D1%2C%5C%20k%3D3)
The function in vertex form is :
![f (x) = (x-1) ^ 2 + 3](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%28x-1%29%20%5E%202%20%2B%203)
Answer:
7
Step-by-step explanation:
yeah-ya.. right?.......
Answer: false. 13 - 5 is not 9
Step-by-step explanation:
Answer:
how old are they im confused
Step-by-step explanation: