1,580 Hectoliters =
1,580,000 Deciliters
Answer: 
Step-by-step explanation:
Let be "x" the height inches (in the model) of a 84 foot building.
According to the information provided in the exercise, we know that the height of a two-story building is 21 feet and in the scale model its height is 3 inches.
Knowing this, we can set up the following proportion:

The final step is to solve for "x" in order to calculate its value. We get that this is:

Therefore, an 84 foot building will be 12 inches tall in the model.
Answer:
2 remainder 5 ily
Step-by-step explanation:
Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer:
(1, -7)
Step-by-step explanation:
the difference between -4 & 6 is 10 so you add 5 (half) to -4 or subtract from 6, this gives you 1
you do the same for -9 and -5, the midpoint for those being -7, I hope this helps