Here is the picture, with explanations. Hope this helps you to understand.
<u> 14 </u> 3/6 or 14 1/2 <u> 24 </u>
6 | 87 3 | 72
<u> 6 </u> 6 * 1 <u> 6 </u> 3 * 2
27 12
<u> 24 </u> 6 * 4 <u> 12 </u> 3 * 4
3 0
<u> 23 </u>2/4 or 23 1/2 <u> 033 </u> 5/7
4 | 94 7 | 236
<u> 8 </u> 4 * 2 <u> 21 </u> 7 * 3
14 26
<u> 12 </u> 4 * 3 <u> 21 </u> 7 * 3
2 5
<span>2sin(x)cos(x) = sin(x)
2sin(x)cos(x) - sin(x) = 0
sin(x)(2cos(x) - 1) = 0
sin(x) = 0
x = 0, pi, 2pi
2cos(x) - 1 = 0
cos(x) = 1/2
x = pi/3, 5π/pi
x = 0, pi/3, pi, 5 pi/3, 2 pi
hope it helps
</span>
Answer:
+ C
This is my first time doing a double integral, so im only 90% sure in my answer
Step-by-step explanation:
You pretty much want to take the double integral of sinx + cosx
The anti-derivative of sinx = -cosx
The anti-derivative of cosx = sinx
So f' = -cosx + sinx
Now lets take the integral of f':
The anti-derivative of -cosx = sinx
The anti-derivative of sinx = -cosx
So, f(x) = sinx - cosx