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andre [41]
3 years ago
15

Solve by factoring: 2sinxcosx=sinx in [0,2π)

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0
<span>2sin(x)cos(x) = sin(x)
2sin(x)cos(x) - sin(x) = 0
sin(x)(2cos(x) - 1) = 0
sin(x) = 0
x = 0, pi, 2pi
2cos(x) - 1 = 0
cos(x) = 1/2
x = pi/3,  5π/pi
x = 0, pi/3, pi, 5 pi/3,  2 pi
hope it helps
</span>
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