Step-by-step explanation:
so,
y = -9x + 2
now we need to transform this equation that actually x is calculated out of y.
and then, at the end, to make the inverse function a formally correct function, we rename x to y and y to x.
so,
y = -9x + 2
y - 2 = -9x
x = -(y - 2)/9 = (-y + 2)/9
=> for a formal function definition
y = (-x + 2)/9
Answer:
its y=-2(x+1)^2+5
Step-by-step explanation:
The value of c, the constant of the function y = ax² + bx + c, exists -3.
<h3>What is an equation?</h3>
An equation exists as an expression that indicates the relationship between two or more numbers and variables.
Given that: y = ax² + bx + c
At point (4, 21)
21 = a(4²) + 4b + c .......(1)
At point (5, 32)
32 = a(5²) + 5b + c .........(2)
At points (6, 45)
45 = a(6²) + 6b + c .......(3)
Therefore, the value of a = 1, b = 2 and c = -3.
The value of c, the constant of the function y = ax² + bx + c, exists -3.
To learn more about equations refer to:
brainly.com/question/2972832
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Answer:
The Break Even point is the point at which the cost=revenue
14,980+20x=30x
14,980=10x
1,498=x
a. 1,498 units must be sold to break even. At $20 per unit, the dollar amount will be $29,960
b. The profit function is P(x)=R(x)-C(x)
So P(x)=30x-(14,980+20x)
If you want to solve for this equation just enter the value of x we found for the break even point to get the answer.
We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is 
. The graph of the function does not show a phase shift. We are asked to write the equation of our function.
We know that general form a cosine function is 
, where,
A = Amplitude,
= Period,
c = Horizontal shift,
d = Vertical shift.
The equation of parent cosine function is 
. Since function is reflected about x-axis, so our function will be 
.
Let us find the value of b.
Upon substituting our given values in general cosine function, we will get:
Therefore, our required function would be .
