Answer: A, B, D, E
Arc PQ is congruent to arc SR.
The measure of arc QR is 150°
Arc PS measures about 13.1 cm.
Arc QS measures about 15.7 cm.
Step-by-step explanation:
No it is not. If you had two fixed diagonals which are attached in the center, when they move it creates different parallelograms. The area would be close to zero if they were parallel.
Consecutive integers are 1 aparrt
they are
x,x+1,x+2,x+3
the 2nd and 4th sum is x+1 and x+3
sum is 34
x+1+x+3=34
2x+4=34
minus 4
2x=30
divide 2
x=15
x+1=16
x+2=17
x+3=18
the numbers are 15,16,17,18
Remark
I think you want us to do both 3 and 4
Three
QR is 4 points going left from the y axis + 2 points going right from the y axis.
QR = 6 units long.
RT is 4 units above the x axis and 3 units below the x axis
RT = 7 units long
TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.
Problem 4
You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.
Area = (b1 + b2)*h/2
Givens
B1 = QR = 6
B2 = UT + TS = 6 + 3 = 9
h = RT = 7
Area
Area = (6 + 9)*7/2
Area = 15 * 7 / 2
Area = 52.5
Comment
You could break this up into a rectangle + a triangle
Find the area of QRTU and add the Area of triangle RTS
<em>Area of the rectangle </em>= L * W
L = RT = 7
W = QR = 6
Area = 7 *6 = 42
<em>Area of the triangle</em> = 1/2 * B * H
B = TS = 3
H = RT =7
Area = 1/2 * 3 * 7
Area = 1/2 * 21
Area = 10.5
Total Area = 42 + 10.5 = 52.5 Both answers agree.
Answer: D. 26 units
Step-by-step explanation: perimeter is the distance around the figure, or all the sides added together.
With a rectangle it is known that the opposite sides are congruent, or the same, so 8+8+5+5 = 26
