Answer:
6kg pure copper and 30 kg 10% copper was mixed to give 36kg of 25% alloy
Step-by-step explanation:
Here, we want to produce 36 kg of 25% alloy
Let the Pure copper be x kg while 10% alloy be y kg
Pure copper is simply 100% copper
Thus;
x + y = 36 •••••(i)
Then;
100% of x + 10% of y = 25% of 36
= x + 0.1y = 9 •••••• ii)
From i x = 36-y
from ii, x = 9-0.1y
Equate both x
36-y = 9-0.1y
36-9 = 0.1y + y
0.9y = 27
y = 27/0.9
y = 30
x = 36-y
x = 36-30
x = 6 kg
Answer:
10
Step-by-step explanation:
12-6+4
<span>10.
if we were to
subsitute the points and graph the equation we would notice that the
shape is the same for both: a 45 degree angle line that goes upleft and
up right
the graph of y=|x| looks like a right angle corner that is facing up that is ballancing on the point (0,0)
the
graph of y=|x|-4 is the same except that the graph is shifter 4 units
to the right ie. the point ofo the graph/rightangle is on point (4,0)
14.
slope intercept form which is y=mx+b
m=slope b=y intercept
m=4/3
y=4/3x+b
one given solution/point is (9,-1)
one solution is x=9 and y=-1 so subsitute and solve fo b
-1=4/3(9)+b
-1=36/3+b
-1=12+b
subtract 12 from both sides
-11=b
the equation si y=4/3x-11
see which one converts to the correct form
after trial and error we find that y-1=4/3(x-9) is the answer
</span>
The answer is 46.125 hope this helped :)
