Find the domain of
y = log(x + 3)
Logarithms can only be taken for positive numbers. So you must have
x + 3 > 0
x > – 3 ✔
So the domain of the function is
D = {x ∈ R: x > – 3}
or using the interval notation
D = (– 3, +∞)
I hope this helps. =)
Add: <span>(−x^3 + 26x^2 − 7x − 13) + (6x^4 − x^3 +8x + 27)
You may find it easier to write these one above the other:
</span><span> (−x^3 + 26x^2 − 7x − 13)
+ (6x^4 − x^3 +8x + 27)
-------------------------------------------
6x^4 -2x^3 + 26x^2 +x + 14 (answer)
Please note: You should use " ^ " to indicate exponentation.
</span><span>6x4 −2x3 + 26x2 +x + 14 NO
</span><span>6x4 −2x^3 + 26x^2 +x + 14 YES
</span>
Answer:
1/3 or 0.333333
Step-by-step explanation:
The question talks about a die that was tossed once and we are now asked to find the probability that it is a figure greater than 4
---A die has 6 faces with the numbers 1,2,3,4,5 and 6 one on each of
the six faces.Considering an unbaised die the probability of any of the faces to appear in a single roll is 1/6.
So, P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=1/6
Now that numbers greater than 4 are 5 and 6
So it can be P(5) or P(6)= P(5)+P(6)=2/6 = 1/3 or 0.33333
Answer 1/3 or 0.33333
Question 1 is A. Question 2 is perpendicular. Question 3 is C. And Question 4 is C
Answer:
its just 16
Step-by-step explanation:
Absoulte value is a whole postive form of a number meaning that 16 is the only answer.
