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Anna007 [38]
2 years ago
13

A paratrooper falls to the ground along a diagonal line. His fall begins 1683 meters above the ground, and the line he follows h

as a slope
of 1.7. That is, he falls 1.7 meters vertically for every 1 meter he moves across horizontally. How far horizontally across the ground does
he land from his initial position in the sky?
Mathematics
1 answer:
iragen [17]2 years ago
4 0

The distance horizontally across the ground the  he land from his initial position is 990 meters.

The slope of a line shows how steep the line is. The slope is calculated using the formula:

Slope = vertical rise / horizontal run

From the question, the slope is 1.7. Hence:

Slope = vertical rise / horizontal run

1.7 = 1683 m / horizontal run

Horizontal run = 990 meters

Hence, the distance horizontally across the ground the  he land from his initial position is 990 meters.

Find out more on slope at: brainly.com/question/3493733

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<em>Hi there!</em>

<em>~</em>

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A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in
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Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

\frac{dr}{dt} =\frac{1}{2} --- rate of the radius

\frac{dh}{dt} =-\frac{1}{3} --- rate of the height

r = 2

h = \frac{1}{3}

Required

Determine the rate of change of the cone volume

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V = \frac{\pi}{3}r^2h

Differentiate with respect to time (t)

\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})

Substitute values for the known variables

\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})

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