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Anna007 [38]
1 year ago
13

A paratrooper falls to the ground along a diagonal line. His fall begins 1683 meters above the ground, and the line he follows h

as a slope
of 1.7. That is, he falls 1.7 meters vertically for every 1 meter he moves across horizontally. How far horizontally across the ground does
he land from his initial position in the sky?
Mathematics
1 answer:
iragen [17]1 year ago
4 0

The distance horizontally across the ground the  he land from his initial position is 990 meters.

The slope of a line shows how steep the line is. The slope is calculated using the formula:

Slope = vertical rise / horizontal run

From the question, the slope is 1.7. Hence:

Slope = vertical rise / horizontal run

1.7 = 1683 m / horizontal run

Horizontal run = 990 meters

Hence, the distance horizontally across the ground the  he land from his initial position is 990 meters.

Find out more on slope at: brainly.com/question/3493733

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Shkiper50 [21]

Answer:

d=48/2.15

Step-by-step explanation:

hope it helps

easy peazy

8 0
2 years ago
Pls help with this!! no wrong answers pls
Juliette [100K]

Answer:

x = 40

Step-by-step explanation:

180 = 100 + x +x

180-100= 2x

80 = 2x

x = 40

4 0
2 years ago
A square has a side length of 4 cm. What is the length of the diagonal of the square? What is the length from the corner to the
masya89 [10]
The length of the diagonal of the square is the square root of 32 which equals approximately 5.6569.
The length from the corner to the center of the square is half of the diagonal which is 2.8284. I hope this helps!
7 0
3 years ago
Volunteers at Sam's school use some of the student council's savings for a special project. They buy 6 backpacks for $4 each and
kaheart [24]

Answer: changed by $48

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Also $4 times 12 = $48

4 0
2 years ago
supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are
Simora [160]
<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu

, where n= sample size

\overline{x} = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : df=n-1=24

\overline{x}= \$93.36

s=\ $19.95

Significance level for 98% confidence interval : \alpha=1-0.98=0.02

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu

=93.36-9.943878< \mu

=93.36-9.943878< \mu

=83.416122< \mu

Hence, the 98% confidence interval for the mean repair cost for the dryers. = 83.4161

4 0
3 years ago
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