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3 years ago

Loremipsumpilokey what 900 x 2

Mathematics

2 answers:

ankoles [38]3 years ago

5 0

Answer:

900 x 2 is 1,800

Step-by-step explanation:

Multiply 9 by 2. You will get 18. Add 2 zeros to the end of your answer.

Temka [501]3 years ago

4 0

Answer:

1800

Step-by-step explanation:

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the function p(t)p(t)p, left parenthesis, t, right parenthesis models the average high temperature, in degrees celsius, of paity

Mnenie [13.5K]

The solution set for the last equation represents the set of all days when the towns have the same average high temperature.

The hotness of matter or radiation is expressed by the physical quantity known as temperature. The average air temperature for a specific time period, often a day, a month, or a year, as measured by a thermometer that has been properly exposed.
P(t) is the average high temperature, in degrees Celsius, of Paityn's town on t days.

$\begin{aligned} P(t)&=22.5+7.5\cos\left(\dfrac{2\pi (t-28)}{365}\right)\\\\ \end{aligned}$

V(t) is the average high temperature, in degrees Celsius, of Vince's town on t days.

$\\ V(t)&=30.5+1.5\cos\left(\dfrac{2\pi (t-90)}{365}\right)$

So, P(t) = V(t) represents the set of all the days when both towns have the same average high temperature.

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1 year ago

Two catalysts may be used in a batch chemical process. Twelve batches were prepared using catalyst 1, resulting in an average yi

aalyn [17]

Answer:

a) $t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

$df=12+15-2=25$

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) $(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

Step-by-step explanation:

Notation and hypothesis

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

Part a

The system of hypothesis on this case are:

Null hypothesis: $\mu_2 \leq \mu_1$

Alternative hypothesis: $\mu_2 > \mu_1$

Or equivalently:

Null hypothesis: $\mu_2 - \mu_1 \leq 0$

Alternative hypothesis: $\mu_2 -\mu_1 > 0$

Our notation on this case :

$n_1 =12$ represent the sample size for group 1

$n_2 =15$ represent the sample size for group 2

$\bar X_1 =85$ represent the sample mean for the group 1

$\bar X_2 =91$ represent the sample mean for the group 2

$s_1=3$ represent the sample standard deviation for group 1

$s_2=2$ represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

$\S^2_p =\frac{(12-1)(3)^2 +(15 -1)(2)^2}{12 +15 -2}=6.2$

And the deviation would be just the square root of the variance:

$S_p=2.490$

Calculate the statistic

And now we can calculate the statistic:

$t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

Now we can calculate the degrees of freedom given by:

$df=12+15-2=25$

Calculate the p value

And now we can calculate the p value using the altenative hypothesis:

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

Conclusion

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Part b

For this case the confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}$

For the 99% of confidence we have $\alpha=1-0.99 = 0.01$ and $\alpha/2 =0.005$ and the critical value with 25 degrees of freedom on the t distribution is $t_{\alpha/2}= 2.79$

And replacing we got:

$(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

7 0

3 years ago

Whats 1+1 Plz help enjoy the points hehe

AleksandrR [38]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Leviafan [203]

All you gotta do is do 11.00 decided by .44 and it’s 25

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3 years ago

If you are driving a train and your going over 180 mph, and you pass 20 houses, 10 stores, 3 gas stations, and 1 hospital per ev

zlopas [31]

If I am driving the train , the colour of the eye will be my eye colour.

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2 years ago