On his trip,Buddy drove 60 mph for 1 hour, 55 mph for 3 hours and 40 mph for 2 hours. What was the distance of Buddy trip?

A forest covers 68,000 acres. A survey finds that 0.8% of the forest is old-growth trees. How many acres of old-growth trees are

I am Lyosha [343]

Answer:

544 acres

Step-by-step explanation:

There is 100% in a whole.

1% is 1/100th of the whole, or 0.01 of it. We get this because 1/100 = 1/100 = 0.01

Similarly, 0.8/100 = 0.008. We then multiply the decimal by the total to get

(0.008) ( 68000) = 544 acres

8 0

3 years ago

Hurricane Maria killed 3,057 people. Round this to the nearest ten, and thousand.

Leya [2.2K]

Answer:

rounded to nearest ten - 3,060

rounded to nearest thousand - 3,000

These should be the answers. Hope this helps!

5 0

3 years ago

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Integral of cosecx dx =log|tanx/2| show that.

Pie

ANSWER:

Let t = logtan[x/2]

⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx

⇒dt = 1/2 cos² x/2 × cot x/2dx

⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx

⇒dt = 1/2 cosx/2 / sin x/2 dx

⇒dt = 1/sinxdx

⇒dt = cosecxdx

Putting it in the integration we get,

∫cosecx / log tan(x/2)dx

= ∫dt/t

= log∣t∣+c

= log∣logtan x/2∣+c where t = logtan x/2

7 0

3 years ago

There has been a great deal of controversy over the last several years regarding what types of surveillance are appropriate to p

alexira [117]

Answer:

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

Step-by-step explanation:

There are 1000 future terrorists in a population of 300,000,000. So the probability that a randomly selected person in this population is a terrorist is:

$P = \frac{1,000}{300,000,000} = 0.000003 = 0.0003%$

So, we have these following probabilities:

A 99.9997% probability that a randomly chosen person is not a terrorist.

A 0.0003% probability that a randomly chosen person is a terrorist.

A 98% probability that a future terrorist is correctly identified

A 99.9% chance of correctly identifying someone who is not a future terrorist. This also means that there is a 0.01% probability of someone who is not a terrorist being identified as one.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Here we have:

What is the probability that the person is a terrorist, given that she was identified as a terrorist.

P(B) is the probability that the person is a terrorist. So $P(B) = 0.000003$

P(A/B) is the probability that the person was identified as a terrorist, given that she is a terrorist. The problem states that the system has a 98% chance of correctly identifying a future terrorist, so $P(A/B) = 0.98$

P(A) is the probability of a person being a identified as a terrorist. So

$P(A) = P_{1} + P_{2}$

$P_{1}$ is the probability that a person is a terrorist and was identified as one. So:

$P_{1} = 0.000003*0.98 = 0.00000294$

$P_{1}$ is the probability that a person is not a terrorist and, but was identified as one. So:

$P_{2} = 0.999997*0.0001 = 0.0000999997$

So

$P(A) = P_{1} + P_{2} = 0.00000294 + 0.0000999997 = 0.000103$

The answer is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.000003*0.98}{0.000103} = 0.028544$

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

3 0

3 years ago

Angie states the following:

kicyunya [14]

The answer is letter D, Angie is incorrect since triangles with two pairs of congruent sides and one pair of congruent angles do not necessarily meet the SAS orientation.

5 0

3 years ago

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