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gregori [183]
3 years ago
12

The angle measures of a triangle are shown in the

Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0
I believe the answer is 10
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IM GOING TO GIVE 251 POINTS TO WHOEVER ANSWER THIS PROBLEM.
Mariulka [41]

Answer:

(x^87*(x^2+4))/54

Step-by-step explanation:

4 0
2 years ago
Find lim h->0 f(9+h)-f(9)/h if f(x)=x^4 a. 23 b. -2916 c. 2916 d. 2925
Svetach [21]

\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = \lim_{h\to0}\frac{(9+h)^4-9^4}h

Carry out the binomial expansion in the numerator:

(9+h)^4 = 9^4+4\times9^3h+6\times9^2h^2+4\times9h^3+h^4

Then the 9⁴ terms cancel each other, so in the limit we have

\displaystyle \lim_{h\to0}\frac{4\times9^3h+6\times9^2h^2+4\times9h^3+h^4}h

Since <em>h</em> is approaching 0, that means <em>h</em> ≠ 0, so we can cancel the common factor of <em>h</em> in both numerator and denominator:

\displaystyle \lim_{h\to0}(4\times9^3+6\times9^2h+4\times9h^2+h^3)

Then when <em>h</em> converges to 0, each remaining term containing <em>h</em> goes to 0, leaving you with

\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = 4\times9^3 = \boxed{2916}

or choice C.

Alternatively, you can recognize the given limit as the derivative of <em>f(x)</em> at <em>x</em> = 9:

f'(x) = \displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h \implies f'(9) = \lim_{h\to0}\frac{f(9+h)-f(9)}h

We have <em>f(x)</em> = <em>x</em> ⁴, so <em>f '(x)</em> = 4<em>x</em> ³, and evaluating this at <em>x</em> = 9 gives the same result, 2916.

8 0
3 years ago
In a problem it says that x is "at most –5." What does this mean?
STatiana [176]
It means that -5 is the range of your answer, it will be less than that.
8 0
3 years ago
Read 2 more answers
Y = 5/x/+2 <br> Does it compress up 2 or stretch up 2
Dmitriy789 [7]

Answer:

It compresses up 2

Step-by-step explanation:

6 0
4 years ago
Plot each pair of values from the table on the coordinate plane
uysha [10]
How do we? We can’t just...umm
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4 years ago
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