$\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}$

3 0

3 years ago

The area of a triangle is 8.50 square inches . The triangles height is 15inches . What is the length of the base?A) 6 inches b)

DochEvi [55]

Answer:

I think you mistyped the question

Step-by-step explanation:

I get 1.13

5 0

3 years ago

Is 11p-7q polynomial

REY [17]

Answer: Yes; this is polynomial.

Specifically, it is a "polynomial EXPRESSION" ; but not a "polynomial equation" ; because it is not an "equation.

There are more than one variables/variable expressions, so it is a polynomial.

7 0

3 years ago

Read 2 more answers

What is the value of x?<br><br><br> Enter your answer in the box

elixir [45]

X=46.2
_____________________________

99.2 + 62 = 161.2
180 -161.2 = 19.8
19.8 + 112 = 131.8
180 - 131.8 = 48.2
48.2 - 2 = 46.2

3 0

3 years ago