Answer:
Mean - 12
Median - 9
Mean - Median = 3
Step-by-step explanation:
math
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The first equation is 
The second equation is 
Generally the first point of intersection of the first and second equation is x = 0
Generally the obtain the second point of intersection of the two equation we equate the two equations
So
=> 
=> 
=> 
Generally the from washer method we have
![V(x) = \int\limits^4_0 {\pi [(H(x))^2 - (G(x))^2]} \, dx](https://tex.z-dn.net/?f=V%28x%29%20%3D%20%20%5Cint%5Climits%5E4_0%20%7B%5Cpi%20%5B%28H%28x%29%29%5E2%20-%20%28G%28x%29%29%5E2%5D%7D%20%5C%2C%20dx)
So

and

So
![V(x) = \int\limits^4_0 {\pi [(16\sqrt{x})^2 - (4x)^2]} \, dx](https://tex.z-dn.net/?f=V%28x%29%20%3D%20%20%5Cint%5Climits%5E4_0%20%7B%5Cpi%20%5B%2816%5Csqrt%7Bx%7D%29%5E2%20-%20%284x%29%5E2%5D%7D%20%5C%2C%20dx)
=> ![V(x) = \int\limits^4_0 {\pi [256x - 16x^2]} \, dx](https://tex.z-dn.net/?f=V%28x%29%20%3D%20%20%5Cint%5Climits%5E4_0%20%7B%5Cpi%20%5B256x%20-%2016x%5E2%5D%7D%20%5C%2C%20dx)
=>![V(x) = \pi [256 \frac{x^2}{2} - 16 \frac{x^3}{3} ]|\left 4} \atop 0}} \right.](https://tex.z-dn.net/?f=V%28x%29%20%3D%20%20%5Cpi%20%5B256%20%5Cfrac%7Bx%5E2%7D%7B2%7D%20-%2016%20%5Cfrac%7Bx%5E3%7D%7B3%7D%20%5D%7C%5Cleft%204%7D%20%5Catop%200%7D%7D%20%5Cright.)
=> ![V(x) = \pi [256 * \frac{ 4^2}{2} - 16 * \frac{4^3}{3} ]](https://tex.z-dn.net/?f=V%28x%29%20%3D%20%20%5Cpi%20%5B256%20%2A%20%5Cfrac%7B%204%5E2%7D%7B2%7D%20%20-%2016%20%2A%20%5Cfrac%7B4%5E3%7D%7B3%7D%20%5D)
=> 
Answer:
There are 30 trees in a grove
Step-by-step explanation:
In this question, we are asked to calculate the number of trees in each grove, if they decided not to count the seven trees counted.
Firstly, we identify that there are 5 different groves which have the same number of set of trees. Since there are no half trees or fractional trees, we must identify that the total number of trees in all the groves must be a multiple of 5.
Now, there are 143, if they decided not to count the 7 trees, the total number of trees in all the grooves would have been 143 + 7 = 150 trees
Now, we proceed to get the number of trees in each of the grooves. To do that, we simply make a division.
Number of trees in each grove = Total number of Trees/5 = 150/5 = 30 trees per grove