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Lena [83]
4 years ago
9

I am confused. what is 5r– 7 = 2r+ 14

Mathematics
1 answer:
Vlada [557]4 years ago
5 0

Answer:

r=7

Step-by-step explanation:

5r-7=2r+14

add sevento both sides

5r=2r+21

Subtract 2r from both sides.

3r=21

divide both sides by 3

r=7

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Help, easy math...........
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Which function can be used to find the number of cells of bacteria in the population at time t
Nonamiya [84]

Answer:

db / dt = kb  

this becomes b(t) = Ce^(kt)  

C = 100, the initial population  

P(1) = 420 = 100 e^(1k)  

4.2 = e^k  

ln 4.2 = k  

a) thus, b(t) = 100 e^(t ln 4.2)  

b) b(3) = 100 e^(3 ln 4.2)  

c) growth constant will still be ln 4.2 (constant percentage of populatioin)  

d) 10000 = 100 e^(t ln 4.2)  

100 = e^(t ln 4.2)  

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Step-by-step explanation:

6 0
3 years ago
You are enlarging a photograph to make a poster. The posterwill be similar to the original photograph. The photograph is6 inches
natka813 [3]

Answer:

Poster’s perimeter = 150 in

Step-by-step explanation:

Given:

Width of poster = 2.5 ft = 2.5 × 12 = 30 in

Find:

Poster’s perimeter.

Computation:

Height of poster = [30×6]/4

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5 0
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Suppose that 20% of the employees of a given corporation engage in physical exercise activities during the lunch hour. Moreover,
Harlamova29_29 [7]

Answer:

a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

Step-by-step explanation:

Question a:

20% of employees engage in physical exercise.

This 20% is composed by:

8% of 60%(males)

x% of 100 - 60 = 40%(females).

Then, x is given by:

0.08*0.6 + 0.4x = 0.2

0.4x = 0.2 - 0.08*0.6

x = \frac{0.2 - 0.08*0.6}{0.4}

x = 0.38

0.38 = 38%

Probability of being a female who engages in exercise:

40% are female, 38% of 40% engage in exercise. So

0.38*0.4 = 0.152

0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.

B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?

40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So

0.62*0.4 = 0.248

0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.

3 0
3 years ago
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