Let us assume the first number to be = x
Let us assume the second number to be = y
Then
x^2 - y^2 = 5
x^2 = y^2 + 5
And
3x^2 - 2y^2 = 19
Multiplying the first equation by -2, we get
- 2x^2 + 2y^2 = - 10
Now subtracting the two equations, we get
x^2 = 9
x = 3
Putting the value of "x" in the first equation, we get
(3)^2 - y^2 = 5
9 - y^2 = 5
y^2 = 4
y = 2
I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
Answer:
(a)
x cubed is
=x^3=x3
5 times the cube of x is
=5x^3=5x3
4 times x is
=4x=4x
the quotient of 4 times x and 3 is
=\frac{4x}{3}=34x
so,
the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is
=5x^3-\frac{4x}{3}=5x3−34x ..........Answer
(b)
5 times cube of x is
=5x^3=5x3
5 times cube of x divided by 4 times x is
=\frac{5x^3}{4x}=4x5x3 ..........Answer
(c)
difference of 5 times x cube and 4 is
=5x^3 -4=5x3−4
so,
the quotient of the difference of 5 times x cube and 4 and x is
=\frac{5x^3-4}{x}=x5x3−4 ...........Answer
(d)
difference of 5 times x and 4 is
=5x-4=5x−4
so,
the cube of the difference of 5 times x and 4 is is
=(5x-4)^3=(5x−4)3 ............Answer
Answer:
24 yards of chain were sold
Step-by-step explanation:
1 ft = 1/3 yd
72 * 1/3 = 24
3n^2 sqrt 5n
hope that helped (:
