_______ are unprocessed facts that a computer feeds on.

What are the benefits of using an ordered list vs. an unordered list? What are the costs?

Rashid [163]

Answer:

The main benefit of the ordered list is that you can apply Binary Search( O( n log n) ) to search the elements. Instead of an unordered list, you need to go through the entire list to do the search( O(n) ).

The main cost of the ordered list is that every time you insert into a sorted list, you need to do comparisons to find where to place the element( O( n log n) ). But, every time you insert into an unsorted, you don't need to find where to place the element in the list ( O(1) ). Another cost for an ordered list is where you need to delete an element, you have an extra cost rearranging the list to maintain the order.

6 0

2 years ago

Which type of image would require you to obtain permission from the author to use the image and possibly pay a royalty to the au

ASHA 777 [7]

Answer:

Copyrighted.

Explanation:

Patent can be defined as the exclusive or sole right granted to an inventor by a sovereign authority such as a government, which enables him or her to manufacture, use, or sell an invention for a specific period of time.

Generally, patents are used on innovation for products that are manufactured through the application of various technologies.

Basically, the three (3) main ways to protect an intellectual property is to employ the use of

I. Trademarks.

II. Patents.

III. Copyright.

Copyright law can be defined as a set of formal rules granted by a government to protect an intellectual property by giving the owner an exclusive right to use while preventing any unauthorized access, use or duplication by others.

Hence, a copyrighted image would require you to obtain permission from the author to use the image and possibly pay a royalty to the author for its use.

7 0

2 years ago

HELP!!!

jeyben [28]

Answer:

A. a tool tip

Explanation:

6 0

2 years ago

Read 2 more answers

explain how a computer screen and the eye interact to produce the variety of colors that we see from the 3 colors that are actua

Dima020 [189]

Answer:

Each pixel of light coming from your computer is made up of a combination of Red, Blue and Green light of different intensities. As this pixel of light is so small your eye only "sees" the combination of those 3 pixels as the intended colour. (as opposed to just red, green and blue light) (This is also known as additive colour mixing)

5 0

2 years ago

Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static

yKpoI14uk [10]

Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

// main method

public static void main(String[] args) {

// create a list of Comparable type

List<Comparable> list = new ArrayList<>();

// add elements

list.add(1);

list.add(2);

list.add(3);

list.add(4);

list.add(5);

list.add(6);

list.add(7);

// print list

System.out.println("\nList : "+list);

// test search method

Comparable a = 7;

System.out.println("\nSearch for 7 : "+search(list,a));

Comparable b = 3;

System.out.println("\nSearch for 3 : "+search(list,b));

Comparable c = 9;

System.out.println("\nSearch for 9 : "+search(list,c));

Comparable d = 1;

System.out.println("\nSearch for 1 : "+search(list,d));

Comparable e = 12;

System.out.println("\nSearch for 12 : "+search(list,e));

Comparable f = 0;

System.out.println("\nSearch for 0 : "+search(list,f));

}

// static method named search takes arguments Comparable list and Comparable parameter

public static boolean search(List<Comparable> list, Comparable par) {

// if list is empty or parameter is null the throw IllegalArgumentException

if(list.isEmpty() || par == null ) {

throw new IllegalArgumentException();

}

// binary search

// declare variables

int start=0;

int end =list.size()-1;

// using while loop

while(start<=end) {

// mid element

int mid =(start+end)/2;

// if par equal to mid element then return

if(list.get(mid).equals(par) )

{

return true ;

}

// if mid is less than parameter

else if (list.get(mid).compareTo(par) < 0 ) {

start=mid+1;

}

// if mid is greater than parameter

else {

end=mid-1;

}

// if not found then retuen false

return false;

}

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

// main method

public static void main(String[] args) {

// create a list of Comparable type

List<Comparable> list = new ArrayList<>();

// add elements

list.add(1);

list.add(2);

list.add(3);

list.add(4);

list.add(5);

list.add(6);

list.add(7);

// print list

System.out.println("\nList : "+list);

// test search method

Comparable a = 7;

System.out.println("\nSearch for 7 : "+search(list,a));

Comparable b = 3;

System.out.println("\nSearch for 3 : "+search(list,b));

Comparable c = 9;

System.out.println("\nSearch for 9 : "+search(list,c));

Comparable d = 1;

System.out.println("\nSearch for 1 : "+search(list,d));

Comparable e = 12;

System.out.println("\nSearch for 12 : "+search(list,e));

Comparable f = 0;

System.out.println("\nSearch for 0 : "+search(list,f));

}

// static method named search takes arguments Comparable list and Comparable parameter

public static boolean search(List<Comparable> list, Comparable par) {

// if list is empty or parameter is null the throw IllegalArgumentException

if(list.isEmpty() || par == null ) {

throw new IllegalArgumentException();

}

// binary search

// declare variables

int start=0;

int end =list.size()-1;

// using while loop

while(start<=end) {

// mid element

int mid =(start+end)/2;

// if par equal to mid element then return

if(list.get(mid).equals(par) )

{

return true ;

}

// if mid is less than parameter

else if (list.get(mid).compareTo(par) < 0 ) {

start=mid+1;

}

// if mid is greater than parameter

else {

end=mid-1;

}

// if not found then retuen false

return false;

}

7 0

2 years ago