Answer:
Save your Blender file (. blend) in the same folder as your . obj file, if you didn't already.
Click on File/External Data/Pack All into . blend.
Click on File/External Data/Unpack All Into Files.
Choose "Use files in current directory (create when necessary)"
Explanation:
<em>Hope </em><em>it </em><em>helps </em><em>ya </em><em>ItzAlex</em>
I think select the video insert select the movie option under illustrations resize the video player then select the insert tab i’m not 100 percent sure tho
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Answer:
see explaination for program code
Explanation:
scalar_product = 0
li=[]
li2=[]
#reading numbers1.txt and numbers2.txt intoli and li2 respectively
with open('numbers1.txt') as n1, open('numbers2.txt') as n2:
for line1 in n1:
li.append(int(line1))
for line2 in n2:
li2.append(int(line2))
#storing min list size into variable l
a=len(li)
b=len(li2)
if a<b:
l=a
else:
l=b
#calculating scalar product
for i in range(l):
scalar_product=scalar_product+li[i]*li2[i]
print("scalar product is",scalar_product)
Answer: A select the picture
