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Ipatiy [6.2K]
3 years ago
12

Does anybody want to be my friend

Computers and Technology
2 answers:
Gekata [30.6K]3 years ago
6 0

Answer:

Yeah sure, mines aatelophxbia, i'm 14. what games you play?

Hunter-Best [27]3 years ago
3 0

Answer:

I have some stuff but besides Xbox

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How do you render and export files on blender
Debora [2.8K]

Answer:

Save your Blender file (. blend) in the same folder as your . obj file, if you didn't already.

Click on File/External Data/Pack All into . blend.

Click on File/External Data/Unpack All Into Files.

Choose "Use files in current directory (create when necessary)"

Explanation:

<em>Hope </em><em>it </em><em>helps </em><em>ya </em><em>ItzAlex</em>

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3 years ago
Drag each tile to the correct box.
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I think select the video insert select the movie option under illustrations resize the video player then select the insert tab i’m not 100 percent sure tho
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Write a script that calculates the common factors between 8 and 24. To find a common factor, you can use the modulo operator (%)
AnnyKZ [126]

Answer:

  1. common = []
  2. num1 = 8
  3. num2 = 24
  4. for i in range(1, num1 + 1):
  5.    if(num1 % i == 0 and num2 % i == 0):
  6.        common.append(i)
  7. print(common)

Explanation:

The solution is written in Python 3.

Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).

Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).

Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i  will be zero and the if block will run to append the current i value to common list (Line 6-8).

After the loop, print the common list and we shall get [1, 2, 4, 8]

8 0
3 years ago
Two files named numbers1.txt and numbers2.txt both have an unknown number of lines, each line consisting of a single positive in
Reika [66]

Answer:

see explaination for program code

Explanation:

scalar_product = 0

li=[]

li2=[]

#reading numbers1.txt and numbers2.txt intoli and li2 respectively

with open('numbers1.txt') as n1, open('numbers2.txt') as n2:

for line1 in n1:

li.append(int(line1))

for line2 in n2:

li2.append(int(line2))

#storing min list size into variable l

a=len(li)

b=len(li2)

if a<b:

l=a

else:

l=b

#calculating scalar product

for i in range(l):

scalar_product=scalar_product+li[i]*li2[i]

print("scalar product is",scalar_product)

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To view the Picture tools tab, a user must first _____.
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Answer: A select the picture
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