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Evgen [1.6K]
3 years ago
11

Which statement is true about parity in RAM?

Computers and Technology
1 answer:
mihalych1998 [28]3 years ago
8 0

Answer:

There needs to be an odd number of 1 bits

Explanation:

In memory, parity checking method is used to test the memory. There are two parity conditions. Either the parity is even or the parity is odd.

Odd parity means, number of 1's in eight bits of data. If the number 1's are odd  it means parity is odd. In case of the memory testing result the parity should be odd.

So, In case of Parity of RAM, the parity should be odd, if the data is stored in the RAM.

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In India, the adoption of new telecommunication services was ____________ Select one: a. slow b. rapid c. frought with errors d.
irina1246 [14]

Answer:

The correct answer is letter "B": rapid.

Explanation:

Nowadays, India has become the second largest telecommunications network in the world. Phone and internet services are very low-price because of the vast number of competitors in the market. This scenario is boosted by the constant improvement technologies being implemented in the country in this matter such as better signaling gateways and fiber-optics. By the end of 2018, India had almost 20% of the world's share of internet users.

6 0
3 years ago
The PATH environment variable.
enot [183]

Answer:

Answer explained below

Explanation:

Yes, you can let Set-uid program that is owned by root to run your code instead of /bin/ls but it has it's own drawbacks and is actually not safe.

As you can not rely on that since some of the shells if different from the ruid drop an euid which is actually not safe.

execl("/bin/ls", "ls",(char *)0);  

run this under your main program.

Since it can have a root previlege,

-$ cd /tmp/

/tmp$ sudo su

:/tmp# gcc -o system system.c

:/tmp# chmod u+s system // changing file permissions

:/tmp# exit

exit

:/tmp$ cp /bin/sh /tmp/ls

:/tmp$ ./system

<u>Steps: </u>

1. The first thing you need to do is copy /bin/sh to /tmp.

2. After copying /bin/sh to /tmp set a new name ls but make sure your sh ->.zsh.

3. Set PATH to current directory. /tmp.

4. Compile

5. Run the program system and you can get your root previledge.

Now, with the above exmaple if you change /bin/sh soo that it points back to /bin/bash and repeat all the previous steps, you will not be able to get your root previledges.

8 0
4 years ago
Online Book Merchants offers premium customers 1 free book with every purchase of 5 or more books and offers 2 free books with e
andrey2020 [161]

Answer:

This question has two parts, first part is about programming about a Player class and second for reading string from user and decide how many time duck string entered by user and terminate if user press goose string.

The explanation of both program (executable code) is given below in explanation section.

Explanation:

//Program 1

#include <iostream>

using namespace std;

int main()

{

 bool isPremiumCustomer;

 int nbooksPurchased;

 int totalBookPurchasedWithOffer;

// bool cutomerType;

 int freeBooks;

 cout<<"Press 1 for Premium Customer and 0 for regular Customer";

 cin>>isPremiumCustomer;

 cout<<"How many books you purchased ";

 cin>>nbooksPurchased;

 

 

switch(isPremiumCustomer)// what type of customer is  

{

case 1://if customer is premium

 if (nbooksPurchased >= 5&&nbooksPurchased<8)// purchase book greater between 5 and 8

  {

   freeBooks=1;//offer free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

   

   cout<<"You purchased total book with offer ";//show total books

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 8)//if premium customer purchase more than 8 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;//show total books

    }

  else{

   cout<<"You purchased total book with no offer ";

    cout<<nbooksPurchased;

   }

  break;

case 0:// if customer is regular customer

 if (nbooksPurchased >= 7&&nbooksPurchased<12)//and purchase book between 7 and 12

  {

   freeBooks=1;// offer 1 free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

   cout<<"You purchased total book with offer ";

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 12)//if purchase 12 or more than 12 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;

    }

 else{

  cout<<"You purchased total book with no offer ";

  cout<<nbooksPurchased;

  }

  break;

 

}

 

 

 

return 0;// terminate the program

 

}

/* program 1 has ended

and program 2 is started from here

#######################################################

*/

#include <iostream>

using namespace std;

int main()

{

string readstring;// take input string from user to enter either "goose" or "duck"

int count=0;//count the number of "duck"

while(readstring!="goose")//run loop, until user do not enter string  

{

 cout<<"Enter the string either goose or duck ";// prompt user to enter the string

 cin>> readstring;// read string from user

 if (readstring=="duck")//if string equal to "duck"

 {

  count=count+1;//count number of duck string enter by user

   

 }

}//exit/terminate the loop, if user enter the goose string

cout<< " Number of duck that were read " ;// show how many duck string entered by user

cout<<count;

return 0;// terminate the program

 

}

6 0
3 years ago
A portable electronic device that can be used in an emergency to stop someone’s heart from going out of rhythm is called a/an
JulsSmile [24]
It is called a Heart pace maker
7 0
3 years ago
Read 2 more answers
Write a program that reads two fractions such as 1/2 and 1/4 and computes and stores the sum, the difference, the product and th
Vesnalui [34]

Answer:

1: #include <iostream>

2: using namespace std;

3: int main()

4: {

5: int a,b,c,d;

6: cout<<"n1: ";

7: cin>>a;

8: cout<<"d1: ";

9: cin>>b;

10: cout<<"n2: ";

11: cin>>c;

12: cout<<"d2: ";

13: cin>>d;

14: int top = (a*d)+(b*c);

15: int bottom = b*d;

16: cout<<"Sum: "<<top<<"/"<<bottom<<"\n";

17: top = (a*d)-(b*c);

18: cout<<"Difference: "<<top<<"/"<<bottom<<"\n";

19: top = a*c;

20: cout<<"Product: "<<top<<"/"<<bottom<<"\n";

21: top = a*d;

22: bottom = b*c;

23: cout<<"Quotient: "<<top<<"/"<<bottom<<"\n";

24: return 0;

25: }

Explanation:

The Program is written in C++ programming language

The Program is left numbered

Line 5 was used for variable declaration.

Variables a,b represents the numerator and denominator of the first fraction

While variables c,d represent the numerator and denominator of the second fraction

Line 6 prints "n1" without the quotes which represents the numerator of the first fraction

Line 7 accepts input for the numerator of the first fraction.

Line 8 prints "d1" without the quotes which represents the denominator of the first fraction

Line 9 accepts input for the denominator of the first fraction.

Line 10 prints "n2" without the quotes which represents the numerator of the second fraction

Line 11 accepts input for the numerator of the second fraction.

Line 12 prints "d2" without the quotes which represents the denominator of the second fraction

Line 13 accepts input for the denominator of the second fraction.

Line 14 and 15 calculate the sum of the fractions which is then printed on line 16

Line 17 calculates the difference of the fractions which is then printed on line 18

Line 19 calculates the product of the fractions which is then printed on line 20

Line 21 and 22 calculates the quotient of the fractions which is then printed on line 23

5 0
3 years ago
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