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pashok25 [27]
3 years ago
7

Find k so that the following function is continuous: f(x)={kx8x2if0≤x<5if5≤x.

Mathematics
1 answer:
tankabanditka [31]3 years ago
3 0

Check the one-sided limits:

\displaystyle \lim_{x\to5^-}f(x) = \lim_{x\to5}kx = 5k

\displaystyle \lim_{x\to5^+}f(x) = \lim_{x\to5}8x^2 = 200

If <em>f(x)</em> is to be continuous at <em>x</em> = 5, then these two limits should have the same value, which means

5<em>k</em> = 200

<em>k</em> = 200/5

<em>k</em> = 40

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Step by step explanation

Here we have to use the formula.

The symmetry of a parabola x = -b/2a

Now compare the given equation y = 3x^2 + 24x -1 with the general form y = ax^2 + bx + c and identify the value of "a" and "b"


Here a = 3 and b = 24. Now plug in these values in to the formula to find the line of symmetry.

x = -24/ 2(3)

x = -24/6

x = -4

Therefore, the line of symmetry x = -4.

Thank you.

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