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Svet_ta [14]
3 years ago
6

Help me please please ​

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

3a^2 - 7a - 6

Step-by-step explanation:

Find the average length of the light gray shaded figure.  It is:

4a + 5 + 2a - 1        6a + 4

--------------------- = --------------- = 3a + 2

            2                      2

Now multiply this average length, 3a + 2, by the width, a - 3:

Area of light gray figure is (3a + 2)(a - 3) = 3a^2 - 7a - 6

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When temperature is zero degree Celsius, the Fahrenheit temperature is 32. When the Celsius temperature is 100, the correspondin
7nadin3 [17]

Answer:

\\ y = 1.8(x) + 32 or \\ y = \frac{9}{5}(x) + 32

or equivalently:

\\ F = 1.8(C) + 32 or \\ F = \frac{9}{5}(C) + 32

Step-by-step explanation:

To express the Fahrenheit temperature <em>as a linear function of the Celsius temperature</em>, F(c), we can proceed as follows.

We can use here <em>the two-point form</em> <em>equation</em> of a line:

\\ y-y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x-x_1) [1]

We are asked to express the <em>Fahrenheit temperature</em> as a function of <em>Celsius temperature</em>, so the independent variable, in this case, is <em>x</em> (Celsius temperature) and the dependent variable is <em>y</em> (Fahrenheit temperature).

When temperature is zero degree Celsius (\\x_1 = 0), the Fahrenheit temperature is 32 (\\y_1 = 32).

When the Celsius temperature is 100 (\\x_2 = 100), the corresponding Fahrenheit temperature is 212 (\\y_2 = 212).

Then, using [1], we have:

\\ y-32 = \frac{212 - 32}{100 - 0}(x-0)

\\ y-32 = \frac{180}{100}(x)

\\ y-32 = 1.8(x).

It could be also be written as:

\\ y-32 = \frac{18}{10}(x) = \\ y-32 = \frac{9}{5}(x), as it commonly appears in books.

Then <em>the Fahrenheit temperature express as a linear function of the Celsius temperature, F(c</em>) is ( solving the equation for <em>y </em>) :

\\ y = 1.8(x) + 32 or \\ y = \frac{9}{5}(x) + 32.

Or equivalently:

\\ F = 1.8(C) + 32 or \\ F = \frac{9}{5}(C) + 32

We can check this using the given values from the question:

For 0 Celsius degrees, the Fahrenheit temperature is:

\\ y = 1.8(0) + 32 = 32 Fahrenheit degrees.

For 100 Celsius degrees, the Fahrenheit temperature is:

\\ y = 1.8(100) + 32 = 180 + 32 = 212 Fahrenheit degrees.

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deff fn [24]
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You are given two points that could be plotted on a graph (1,-5) and (4,1). The formula for slope is y2-y1/x2 -x1

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