Answer:
2 rad/s
Explanation:
For a rotating object, the linear velocity is given by
where is the angular velocity and
is the radius.
The edge has a linear velocity of 10 m/s and the radius at the edge is 5 m.
Question 15 plz picture above
1 answer:
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Answer:
a) 9.00 m b) 6.00 m/s c) 12.00 m/s
Explanation:
a) If the acceleration is constant, and we know that the displacement during the first second was 3.00 m, as the boulder (assumed that we can treat it as a point mass) started from rest, we can say the following:
Δx = = 3.00 m
As t = 1 s, replacing in the expression above, and solving for a, we have:
= 6.00 m/s²
In order to know how far it travels during the second second, we need to know the value of the speed after the first second, as it is the initial velocity when the second second begins:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
The total displacement, during the second second, will be as follows:
Δx = v₀*t + = 6.00m/s*1s +
⇒ Δx = 9.00 m
b) At the end of the first second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
c) At the end of the second second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*2s = 12.00 m/s
given that acceleration due to gravity is g = 10 m/s^2
speed of the rocket will reach to 0.9c
now by kinematics
Part b)
distance traveled by it in above time
so this is the distance covered by the object