Answer:
![F=1.26*10^{-3}N](https://tex.z-dn.net/?f=F%3D1.26%2A10%5E%7B-3%7DN)
Explanation:
Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:
![F=\frac{kq_1q_2}{d^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_1q_2%7D%7Bd%5E2%7D)
We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(
) and inversely proportional to the square of the distance(d) that separates them.
Replacing the given values, where k is the Coulomb constant:
![F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B8.99%2A10%5E%7B9%7D%5Cfrac%7BN%5Ccdot%20m%5E2%7D%7BC%5E2%7D%28-30%2A10%5E%7B-9%7DC%29%28-30%2A10%5E%7B-9%7DC%29%7D%7B%288%2A10%5E%7B-2%7Dm%29%5E2%7D%5C%5CF%3D1.26%2A10%5E%7B-3%7DN)
Answer:
Explanation:
circumference of the tyre = 2πr = 2 x 3.14 x 0.26 = 1.6328m
76000km = 76000000m
no of revolutions required
= 76000000/1.6328 = 46546 revolutions.
Answer:
1.01 × 10⁵ Pa
Explanation:
At the surface, atmospheric pressure is 1.013 × 10⁵ Pa.
We need to find the total pressure on the air in the lungs of a person to a depth of 1 meter.
Pressure at a depth is given by :
![P=\rho gh](https://tex.z-dn.net/?f=P%3D%5Crho%20gh)
Where
is the density of air, ![\rho=1.225\ kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D1.225%5C%20kg%2Fm%5E3)
So,
![P=1.225\times 9.8\times 1\\\\=12\ Pa](https://tex.z-dn.net/?f=P%3D1.225%5Ctimes%209.8%5Ctimes%201%5C%5C%5C%5C%3D12%5C%20Pa)
Total pressure, P = Atmospheric pressure + 12 Pa
= 1.013 × 10⁵ Pa + 12 Pa
= 1.01 × 10⁵ Pa
Hence, the total pressure is 1.01 × 10⁵ Pa.
Answer:
Drums, harps, recorders, and bagpipes.
Explanation:
Answer:
a) 32.58 m/s²
b) 161.84 m/s
Explanation:
Initial velocity = u = 0
Final velocity = v = 145 m/s
Time taken = t = 4.45 s
s = Displacement of dragster = 402 m
a = Acceleration
![v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{145-0}{4.45}\\\Rightarrow a=32.58\ m/s^2](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20a%3D%5Cfrac%7Bv-u%7D%7Bt%7D%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B145-0%7D%7B4.45%7D%5C%5C%5CRightarrow%20a%3D32.58%5C%20m%2Fs%5E2)
![v^2-u^2=2as\\\Rightarrow v=\sqrt{2as-u^2}\\\Rightarrow v=\sqrt{2\times 32.58\times 402-0^2}\\\Rightarrow v=161.84\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2as-u%5E2%7D%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2%5Ctimes%2032.58%5Ctimes%20402-0%5E2%7D%5C%5C%5CRightarrow%20v%3D161.84%5C%20m%2Fs)
The final velocity is greater than the velocity used to find the average acceleration due to the gear changes. The first gear in a dragster has the most amount of toque which means the acceleration will be maximum. The final gears have less torque which means the acceleration is lower here. The final gears have less acceleration but can spin faster which makes the dragster able to reach higher speeds but slowly.