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arlik [135]
3 years ago
11

Can someone help me it will for sure help alot someone who is confident on doing it WILL GIVE BRAINLIEST

Mathematics
1 answer:
KengaRu [80]3 years ago
3 0

Answer:

....................

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The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an
Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w  feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = \dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, w = \dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}

Or, w = \dfrac{-11\pm \sqrt{473}}{2}

or, w = \dfrac{-11\pm 21.7}{2}

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0
3 years ago
Match the terms below to their definition. Circumcenter
Natasha_Volkova [10]

Answer:

passes through all verrtices of a polygon

Step-by-step explanation:

4 0
3 years ago
Find the critical value of x2 based on the given information H1 >3.5 n=14 a=0.05
egoroff_w [7]

Answer:

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

\chi^2_{\alpha}= 22.362

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

Step-by-step explanation:

We have the followign system of hypothesis:

Null hypothesis: \sigma^2 \leq 3.5

Alternative hypothesis: \sigma^2 >3.5

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

\chi^2_{\alpha}= 22.362

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

4 0
3 years ago
Consider the function f(x)= 2/5x-4
Gre4nikov [31]

Answer: a) \frac{5}{2}x+10=f^{-1}(x)=g(x)

Step-by-step explanation:

Since we have given that

f(x)=\frac{2}{5}x-4

a.) Find the inverse of f(x) and name it g(x).

Let f(x) = y

So, it becomes

y=\frac{2}{5}x-4

Switching x to y , we get

x=\frac{2}{5}y-4

5x=2y-20\\\\5x+20=2y\\\\\frac{5x+20}{2}=y\\\\\frac{5}{2}x+10=y\\\\\frac{5}{2}x+10=f^{-1}(x)=g(x)

b) . Use composition to show that f(x) and g(x) are inverses of each other.

\mathrm{For}\:f=\frac{2}{5}x-4\:\\\\\mathrm{substitute}\:x\:\mathrm{with}\:g\left(x\right)=\frac{5}{2}x+10\\\\=\frac{2}{5}\left(\frac{5}{2}x+10\right)-4\\\\=x

Similarly,

\mathrm{g\left(x\right)=\frac{5}{2}x+10,\:f\left(x\right)=\frac{2}{5}x-4,\:g\left(x\right)\circ \:f\left(x\right)}\\\\\mathrm{For}\:g=\frac{5}{2}x+10\:\mathrm{substitute}\:x\:\mathrm{with}\:f\left(x\right)=\frac{2}{5}x-4\\\\=\frac{5}{2}\left(\frac{2}{5}x-4\right)+10\\\\=x

so, both are inverses of each other.

c) Draw the graphs of f(x) and g(x) on the same coordinate plane.

As shown below in the graph , Since for inverse function we need an axis of symmetry i.e. y=x

And both f(x) and g(x) are symmetry to y=x.

∴ f(x) and g(x) are inverses of each other.


5 0
3 years ago
How do you do this? I can't remember
Hitman42 [59]
14.75 depending on if the model is 8 & the actual is 1 in the 1:8 scale factor because you would just multiply the actual by 8 because it is the scale factor. the answer could also be .23 is the model is 1 & the actual is 8 because you would divide the actual by 8! hope this helps!!
3 0
3 years ago
Read 2 more answers
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