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3 years ago

100 Points for this

Mathematics

2 answers:

4vir4ik [10]3 years ago

7 0

Answer:

l(x,y) = (-4y, -4x - 3)

Step-by-step explanation:

Let's start with function (x, y)

Transformations in the given order result in following

A dilation by a factor of 4 with the origin as the center of dilation

This results in both coordinates multiplied by 4
(x, y) → (4x, 4y)

A reflection across the y-axis

This results in x-coordinate changing sign to opposite
(4x, 4y) → (-4x, 4y)

A 90° counterclockwise rotation about the origin

This results in x-coordinate swapping with negative y-coordinate
(-4x, 4y) → (-4y, -4x)

A translation 3 units down

This results in y-coordinate change by -3
(-4y, -4x) → (-4y, 4x - 3)

The final function is:

l(x) = (-4y, -4x - 3)

Temka [501]3 years ago

5 0

Answer:

l(x) = (-4y, -4x - 3)

I got the same answer as Mhanifa and if you want the explanation check his, because mine sucks :(

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3 years ago

What are the vertices of triangle A'B'C' produced by (x, y) -> (x+5, y-2)?

lara [203]

Answer:

The vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

A'(8, -2)

B'(8, 0)

C'(5, -5)

Step-by-step explanation:

Given the vertices of an original triangle ΔABC such that

A = (3, 0)

B = (3, 2)

C = (0, -3)

As the rule of translation is given by

Translation: (x, y) → (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0) → (x+5, y-2) ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2) → (x+5, y-2) ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2) ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

A'(8, -2)

B'(8, 0)

C'(5, -5)

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