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3 years ago

A function hall charges $250 fee to rent the hall plus $15 per guest.vwrite an equation for this function

Mathematics

2 answers:

m_a_m_a [10]3 years ago

7 0

Answer:

y=15x+250 (x is the number of guests)

Step-by-step explanation:

the 15 is the slope, so that is the number that has to be multiplied by. The 250 is an additional fee that doesn't change, so it's just added on.

irina1246 [14]3 years ago

3 0

Answer: 250+15

Step-by-step explanation:

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Zolol [24]

Answer:

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Which quadrant would (0,-7) , (0,0) , (8,0)

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Step-by-step explanation:

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3 years ago

What are the coordinates of the center and the

Misha Larkins [42]

Answer: The coordinate of the center is (4,-3)

radius = 8

Step-by-step explanation:

Given ;

$x^{2} +y^{2}=8x-6y+39$

re - arranging , we have

$x^{2} +y^{2}-8x+6y-39=0$

comparing with the general equation

$x^{2} +y^{2}+2gx+2fy+c=0$

This means that

$2gx = -8x$

$2g=-8$

$g=-4$

also

$2fy=6y$

$2f=6$

$f=3$

$c=-39$

The coordinate of the center is (-g,-f)

Therefore;

the coordinate of the center = (4,-3)

the formula for calculating r is given by:

$r = \sqrt{g^{2}+f^{2}-c}$

$r = \sqrt{16+9+39}$

$r=\sqrt{64}$

$r=8$

METHOD 2

$x^{2} +y^{2}-8x+6y-39=0$

using completing the square method , we have

$x^{2} -8x+y^{2}+6y-39=0$

completing the square , we have

$(x-4)^{2}+(y+3)^{2} = 39 +4^{2}+3^{2}$

$(x-4)^{2}+(y+3)^{2}=64$

comparing with the general equation

$(x-a)^{2}+(y-b)^{2}=r^{2}$

where a and b are the coordinate of the center , that is

the coordinate of the center is ( 4 , -3)

$r^{2}=64$

$r=8$

6 0

3 years ago

Through: (-4, 1) and (-5, -5)

mote1985 [20]

Slope would be 6 because -5-1/ -5+4 equals -6/-1 or 6

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3 years ago