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Akimi4 [234]
3 years ago
13

PLs help me ASAP I DONT have time to answer this question, pls show proof on why it’s that answer, it also detects if it’s right

or wrong.

Mathematics
1 answer:
kumpel [21]3 years ago
7 0
<h2><u>15 feet</u> is the correct answer!</h2><h2></h2><h3>6 ÷ 2 = 3</h3><h3><em>h</em> ÷ 5 = 3</h3><h3>3 x 5 = 15</h3><h3 /><h3><em>Please let me know if I am wrong.</em></h3><h3 />
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Jacob is going on a road trip across the country. He covers 10 miles in 15 minutes. He then spends 10 minutes buying gas and som
baherus [9]

Answer:

The distance traveled between 10 minutes and 15 minutes is increasing.

Step-by-step explanation:

Jacob is going on a road trip across the country. He covers 10 miles in 15 minutes.

Therefore, between the 10 minutes and 15 minutes, Jacob was in motion and if he covers 10 miles in 15 minutes with a constant speed, then Jacob will cover \frac{10}{15} \times (15 - 10) =  3.33 miles in that period.

So, the distance traveled between 10 minutes and 15 minutes is increasing.

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3 years ago
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The perimeter of a square piece of gold is 60 millimeters. How long is each side of the piece of gold?
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For Bill's birthday his mom is bringing donuts to school.
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36 donuts (2 1/2 dozen) = $8.00

So, you divide 8 by 36 and you get about 22¢ for each donut. Then, you do .22 x 12 which equals $2.64.

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3 years ago
A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2​, drawn from the 11​, will
svet-max [94.6K]

The required probability is \frac{36}{55}

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.  

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, \text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}

Probability for first draw to be non-defective =\frac{11-2}{11}=\frac{9}{11}

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Probability for second draw to be non defective =\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}

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7 0
3 years ago
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Answer:

a number plus 14

fourteen more than a number

a number increased by 14

Step-by-step explanation:

The phrases which can be represented by the algebraic expression x + 14 are

Let x = the unknown number

a number plus 14

= x + 14

fourteen more than a number

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a number increased by 14

x + 14

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